java - 如何按 Map<String, Integer> 值的降序获取前 10 个键

Question

map.put("Tom",5);
map.put("Tim",2);
map.put("Ted",4);

然后我可以像这样广播它:

Tom is 5
Ted is 4
Tim is 2

我该怎么做？我是编码初学者，请不要这么严厉地惩罚我。

Answer 1

你可以尝试这样的事情:

List<Entry<String, Integer>> l = new ArrayList<>(map.entrySet());

Collections.sort(l, new Comparator<Entry<?, Integer>>() {
    @Override
    public int compare(Entry<?, Integer> a, Entry<?, Integer> b) {
        return b.getValue().compareTo(a.getValue());  // reverse order
    }
});

for (int i = 0; i < 10; i++) {
    Entry<String, Integer> e = l.get(i);
    System.out.println(e.getKey() + " is " + e.getValue());
}

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引用:

• Map.entrySet()
• Collections.sort()
• Comparator