javascript - 从表单上传文件中读取文件内容

Question

我使用下面的代码从文件系统中读取get文件 该代码来自名为 Building a File Uploader with NodeJs 的博客文章.

当我运行我的项目时，我能够看到 UI 等。

我不能使用下面的代码，因为我的项目中没有 uploads 文件夹 (form.uploadDir)

app.post('/upload', function(req, res){

    // create an incoming form object
    var form = new formidable.IncomingForm();

    // specify that we want to allow the user to upload multiple files in a single request
    form.multiples = true;

    // store all uploads in the /uploads directory - cannot use it
    //form.uploadDir = path.join(__dirname, '/uploads');

    // every time a file has been uploaded successfully,
    // rename it to it's original name
    form.on('file', function(field, file) {
        fs.rename(file.path, path.join(form.uploadDir, file.name));
    });

    // log any errors that occur
    form.on('error', function(err) {
        console.log('An error has occurred: \n' + err);
    });

    // once all the files have been uploaded, send a response to the client
    form.on('end', function() {
        res.end('success');
    });
    // parse the incoming request containing the form data
    form.parse(req);

});

My question is how should I get the file from the UI with the code above? I need to get the file content from the form when I choose my file.

应用程序被部署到云端，当我使用localhost时，我使用以下代码(有效)

const readStream = fs.createReadStream("./file.html");

...

const writeStream = sftp.createWriteStream("/index.html");

...

readStream.pipe(writeStream);

它从具有正确路径的文件系统创建一个文件并用另一个文件覆盖它(如这里的 index.html)。

Answer 1

正如@aedneo 所说，当用户选择文件时，文件会在上传文件夹中创建，我只需要重命名它并为写入流方法提供正确的路径即可!