javascript - 检查多个对象属性的值并删除它们

Question

我有一个这种格式的数据集:

{
  roof: 'black',
  door: 'white',
  windows: 8
},
{
  roof: 'red',
  door: 'green',
  windows: 2
},
{
  roof: 'black',
  door: 'green',
  windows: 8
}

我想删除 roof: 'black'、door: 'green' 和 windows: 2 的每个键/值对, 来自每个对象。我所做的如下:

if (object.roof == 'black'){
  delete object.roof;
}

if (object.windows == 2){
  delete object.windows;
}

if (object.door == 'green'){
  delete object.door;
}

但是感觉有点丑。有没有其他更好的方法来实现这一点？

Answer 1

您可以为键值/对获取一个对象，并通过先前的检查删除属性。

var array = [{ roof: 'black', door: 'white', windows: 8 }, { roof: 'red', door: 'green', windows: 2 }, { roof: 'black', door: 'green', windows: 8 }],
    remove = { roof: 'black', windows: 2, door: 'green' };

array.forEach(o => 
    Object.entries(remove).forEach(([k, v]) =>
        o[k] === v && Reflect.deleteProperty(o, k)));

console.log(array);

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