我有以下函数,它返回一个 Promise,其中函数参数是一个异步函数:
createObjectFrom(record) {
const self = this;
return new Promise(async (resolve, reject) => {
let obj = {};
for(let i = 0, l = self.opts.transformers.length; i < l; i++) {
let transformer = self.opts.transformers[i];
const headerIndex = findIndex(self.headers, (header) => {
return header === transformer.column;
});
let csvValue = record[headerIndex];
const lookUp = transformer.options.lookUp;
const whereClause = {};
whereClause[lookUp.column] = csvValue;
console.log('before await');
const result = await self.knex(lookUp.table).where(whereClause).select(lookUp.scalar);
console.dir(result);
obj[transformer.field] = result[0][lookUp.scalar];
}
return resolve(obj);
});
}
如果我在测试中调用这样的函数,它都会正确执行:
it('creates the transformed object', async () => {
const csvRecord = ['PREMIER', '07/11/1998', manager, 'Liverpool', 'Wimbledon', 0, 1, 'A', 0, 1, 'A'];
const record = await transformer.createObjectFrom(csvRecord);
expect(record.division).to.equal('PREMIER');
}
但是在 readable 期间调用 createObjectFrom
函数时从 csv-parse 创建的流中引发的事件:
onReadable() {
let record = this.parser.read();
if (record === null) {
return;
}
if (this.parser.count <= 1) {
this.headers = record;
} else {
const recordPromises = this.createObjectFrom(record);
this.recordPromises.push( newRecord );
}
}
代码在 createObjectFrom
console.log
语句
console.log('before here');
const result = await self.knex(lookUp.table).where(whereClause).select(lookUp.scalar);
console.dir(result);
但没有到达下面的 console.dir
语句,因为 Promise 似乎没有解决。
如果我从流处理之外的测试中调用 createObjectFrom
,那么它会正确解析。
我也尝试重构 async await 以返回一个 promise,但它仍然失败了。
If I console.dir the promises on the [end][3] event of the stream they look like this:
[ Promise {
_bitField: 0,
_fulfillmentHandler0: undefined,
_rejectionHandler0: undefined,
_promise0: undefined,
_receiver0: undefined },
Promise {
_bitField: 0,
_fulfillmentHandler0: undefined,
_rejectionHandler0: undefined,
_promise0: undefined,
_receiver0: undefined } ]
我有this包含源代码和失败测试的 repo。
我对发生的事情感到困惑。
下面的测试也通过了,所以肯定和流有关:
it('creates the transformed object', async () => {
const csvRecords = [
['PREMIER', '07/11/1998', manager, 'Liverpool', 'Wimbledon', 0, 1, 'A', 0, 1, 'A'],
['PREMIER', '11/11/1998', manager, 'QPR', 'Sunderland',3,3, 'Sunderland',0,0,'Sunderland'],
['PREMIER', '14/11/1998', manager, 'Southampton', 'Liverpool', 3, 3, 'D', 0, 0, 'D']
];
for(var i = 0, l = csvRecords.length; i < l; i++) {
const csvRecord = csvRecords[i];
const record = await transformer.createObjectFrom(csvRecord);
expect(record.division).to.equal('PREMIER');
expect(record.manager_id).to.equal(manager_id);
}
}
最佳答案
为什么你不这样改变你的代码:
createObjectFrom: async (record) => {
const self = this;
// return new Promise(async (resolve, reject) => {
let obj = {};
for(let i = 0, l = self.opts.transformers.length; i < l; i++) {
let transformer = self.opts.transformers[i];
const headerIndex = findIndex(self.headers, (header) => {
return header === transformer.column;
});
let csvValue = record[headerIndex];
const lookUp = transformer.options.lookUp;
const whereClause = {};
whereClause[lookUp.column] = csvValue;
console.log('before await');
const result = await self.knex(lookUp.table).where(whereClause).select(lookUp.scalar);
console.dir(result);
obj[transformer.field] = result[0][lookUp.scalar];
}
return obj;
// return resolve(obj);
// });
}
关于javascript - 异步等待或 promise 不返回流事件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39362136/