我正在学习本教程:http://jtreminio.com/2013/03/unit-testing-tutorial-part-5-mock-methods-and-overriding-constructors/ .了解 PHPUnit 工作原理的绝佳教程。
但是我无法理解,因为测试没有通过。
失败是:
Method was expected to be called 1 times, actually called 0 times.
这部分代码:
$badCode->expects($this->once())
->method('checkPassword')
->with($password);
但这是不可能的,因为下一个软断言在 checkPassword 方法中运行并通过测试。
$badCode->expects($this->once())
->method('callExit');
它失败是因为是模拟方法并且行为不同?还是代码错了?
为了便于理解,我附上了所有文件,这是一个小例子。
控制台
PHPUnit 3.7.18 by Sebastian Bergmann.
FYOU SHALL NOT PASS............
Time: 0 seconds, Memory: 6.00Mb
There was 1 failure:
1) phpUnitTutorial\Test\BadCodeTest::testAuthorizeExitsWhenPasswordNotSet
Expectation failed for method name is equal to <string:checkPassword> when invoked 1 time(s).
Method was expected to be called 1 times, actually called 0 times.
FAILURES!
Tests: 13, Assertions: 14, Failures: 1.
BadCode.php
<?php
namespace phpUnitTutorial;
class BadCode
{
protected $user;
public function __construct(array $user)
{
$this->user = $user;
}
public function authorize($password)
{
if ($this->checkPassword($password)) {
return true;
}
return false;
}
protected function checkPassword($password)
{
if (empty($user['password']) || $user['password'] !== $password) {
echo 'YOU SHALL NOT PASS';
$this->callExit();
}
return true;
}
protected function callExit()
{
exit;
}
}
BadCodeTest.php
<?php
namespace phpUnitTutorial\Test;
class BadCodeTest extends \PHPUnit_Framework_TestCase
{
public function testAuthorizeExitsWhenPasswordNotSet()
{
$user = array('username' => 'jtreminio');
$password = 'foo';
$badCode = $this->getMockBuilder('phpUnitTutorial\BadCode')
->setConstructorArgs(array($user))
->setMethods(array('callExit'))
->getMock();
$badCode->expects($this->once())
->method('checkPassword')
->with($password);
$badCode->expects($this->once())
->method('callExit');
$this->expectOutputString('YOU SHALL NOT PASS');
$badCode->authorize($password);
}
}
有人可以帮助我吗?谢谢!
更新
博客的作者用解决方案更新了教程。 不能对模拟方法进行任何断言,只能对 stub 进行断言。
BadCode.php
<?php
namespace phpUnitTutorial;
class BadCode
{
protected $user;
public function __construct(array $user)
{
$this->user = $user;
}
public function authorize($password)
{
if ($this->checkPassword($password)) {
return true;
}
return false;
}
protected function checkPassword($password)
{
if (empty($this->user['password']) || $this->user['password'] !== $password) {
echo 'YOU SHALL NOT PASS';
$this->callExit();
}
return true;
}
protected function callExit()
{
exit;
}
}
BadCodeTest.php
<?php
namespace phpUnitTutorial\Test;
class BadCodeTest extends \PHPUnit_Framework_TestCase
{
public function testAuthorizeExitsWhenPasswordNotSet()
{
$user = array('username' => 'jtreminio');
$password = 'foo';
$badCode = $this->getMockBuilder('phpUnitTutorial\BadCode')
->setConstructorArgs(array($user))
->setMethods(array('callExit'))
$badCode->expects($this->once())
->method('callExit');
$this->expectOutputString('YOU SHALL NOT PASS');
$badCode->authorize($password);
}
}
最佳答案
作者在这里 - 我捏造了那部分,AppFog(我的主机)在使用免费帐户(我的)时遇到问题,所以我现在无法更新它。
此外,是的,它应该是 checkPassword()
中的 $this->user
关于php - 软断言和模拟方法测试失败,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15817394/