php - JSON/数组到 MySQL

Question

我从来没有使用过 JSON 或多维数组，我完全迷失了 atm... 我尝试将来自 coinwarz 的 api 数据写入 MySQL...

我得到的:

{"Success":true,"Message":"999 api calls remaining.","Data":[{"CoinName":"Tagcoin","CoinTag":"TAG","Algorithm":"Scrypt","Difficulty":48.8082576,"BlockReward":30,"BlockCount":35404,"ProfitRatio":8152.1820299065312,"AvgProfitRatio":5538.592714864395,"Exchange":"Cryptsy","ExchangeRate":0.0015114,"ExchangeVolume":9100.58740501,"IsBlockExplorerOnline":true,"IsExchangeOnline":true,"Message":"Warning: The blockchain for this coin is currently having issues. Waiting on a fix from the coin development team.","BlockTimeInSeconds":240,"HealthStatus":"Unhealthy"},{"CoinName":"Lottocoin","CoinTag":"LOT","Algorithm":"Scrypt","Difficulty":12.15941137,"BlockReward":32896,"BlockCount":136845,"ProfitRatio":6884.8588238209768,"AvgProfitRatio":4448.5624688234475,"Exchange":"Cryptsy","ExchangeRate":2.9E-07,"ExchangeVolume":382804480.23628891,"IsBlockExplorerOnline":true,"IsExchangeOnline":true,"Message":"","BlockTimeInSeconds":30,"HealthStatus":"Healthy"},{"CoinName":"RonPaulcoin","CoinTag":"RPC","Algorithm":"Scrypt","Difficulty":30.33885125,"BlockReward":1,"BlockCount":15421,"ProfitRatio":6189.8644790289609,"AvgProfitRatio":8893.1681194248831,"Exchange":"Cryptsy","ExchangeRate":0.0214,"ExchangeVolume":1719.73666494,"IsBlockExplorerOnline":true,"IsExchangeOnline":true,"Message":"","BlockTimeInSeconds":120,"HealthStatus":"Healthy"},{"CoinName":"Franko","CoinTag":"FRK","Algorithm":"Scrypt","Difficulty":1.00168131,"BlockReward":0.25,"BlockCount":406926,"ProfitRatio":6176.3105781107906,"AvgProfitRatio":2511.7635333807175,"Exchange":"Cryptsy","ExchangeRate":0.00282002,"ExchangeVolume":17011.99409075,"IsBlockExplorerOnline":true,"IsExchangeOnline":true,"Message":"","BlockTimeInSeconds":30,"HealthStatus":"Healthy"},

我解码了 ($json_array = json_decode($json_source, true);) 并得到了这个:

Array ( [Success] => 1 
[Message] => 1,000 api calls remaining. 
[Data] => Array ( 

[0] => Array ( [CoinName] => Tagcoin 
[CoinTag] => TAG 
[Algorithm] => Scrypt 
[Difficulty] => 20.62668283 
[BlockReward] => 30 
[BlockCount] => 35339 
[ProfitRatio] => 19310.667769105 
[AvgProfitRatio] => 6361.5043045259 
[Exchange] => Cryptsy 
[ExchangeRate] => 0.001513 
[ExchangeVolume] => 7711.03038846 
[IsBlockExplorerOnline] => 1 
[IsExchangeOnline] => 1 
[Message] => Warning: The blockchain for this coin is currently having issues. Waiting on a fix from the coin development team. 
[BlockTimeInSeconds] => 240 
[HealthStatus] => Unhealthy ) 

[1] => Array ( 
[CoinName] => Dogecoin 
[CoinTag] => DOGE 
[Algorithm] => Scrypt 
[Difficulty] => 1055.45317084 
[BlockReward] => 500000 
[BlockCount] => 76150 
[ProfitRatio] => 7025.6132683628 
[AvgProfitRatio] => 5524.6490817022 
[Exchange] => Vircurex 
[ExchangeRate] => 1.69E-6 
[ExchangeVolume] => 100375791.08525 
[IsBlockExplorerOnline] => 1 
[IsExchangeOnline] => 1 
[Message] => 
[BlockTimeInSeconds] => 60 
[HealthStatus] => Healthy ) 

[2] => Array ( 
[CoinName] => BBQCoin 
[CoinTag] => BQC 
[Algorithm] => Scrypt 
[Difficulty] => 2.04374031 
[BlockReward] => 42 
[BlockCount] => 742772 
[ProfitRatio] => 5980.0470554874 
[AvgProfitRatio] => 2822.26794798 
[Exchange] => Cryptsy 
[ExchangeRate] => 3.316E-5 
[ExchangeVolume] => 81528.3775313 
[IsBlockExplorerOnline] => 1 
[IsExchangeOnline] => 1 
[Message] => 
[BlockTimeInSeconds] => 60 
[HealthStatus] => Healthy ) 

因此，如果我想将其保存到 mysql 中，我将插入

• $json_array[0][CoinName]
• .
• .
• $json_array[1][CoinName]
• .
• .

用 foreach 依此类推。

有没有更好的办法？

---

这样试过:

<?php

$db_host                                = "localhost";
$db_user                                = "test";
$db_pw                                  = "test";
$db_name                                = "test";

$db_connect = mysql_connect($db_host,$db_user,$db_pw); // MYSQL-Connection
mysql_select_db($db_name, $db_connect); // DB-Connection


$url = 'http://127.0.0.1/jsontestdaten.json';
$json_source = file_get_contents($url);

// DUMP JSON
//$data = json_decode($JSON);
//var_dump($data);

$json_array = json_decode($json_source, true);


if(is_array($json_array)){
echo 'i am in array ';
    $sql = "INSERT INTO data (id, coinname, cointag, algorithm, difficulty, blockreward, blockcount, profitratio, avgprofitratio, exchange, exchangerate, exchangevolume, isblockexploreronline, isexchangeonline, message, blocktimeinsecon
        $valuesArr = array();
                foreach($json_array as $row){
                        $coinname               = $row['CoinName'];
                        $cointag                = $row['CoinTag'];
                        $algorithm              = $row['Algorithm'];
                        $difficulty             = $row['Difficulty'];
                        $blockreward            = $row['BlockReward'];
                        $blockcount             = $row['BlockCount'];
                        $profitratio            = $row['ProfitRatio'];
                        $avgprofitratio         = $row['AvgProfitRatio'];
                        $exchange               = $row['Exchange'];
                        $exchangerate           = $row['ExchangeRate'];
                        $exchangevolume         = $row['ExchangeVolume'];
                        $isblockexploreronline  = $row['IsBlockExplorerOnline'];
                        $isexchangeonline       = $row['IsExchangeOnline'];
                        $message                = $row['Message'];
                        $blocktimeinseconds     = $row['BlockTimeInSeconds'];
                        $healthstatus           = $row['HealthStatus'];

$valuesArr[] = "('', '$coinname', '$algorithm','$difficulty','$blockreward','$blockcount','$profitratio','$avgprofitratio','$exchange','$exchangerate','$exchangevolume', '$isblockexploreronline','$message','$blocktimeinseconds','$health
                        }
$sql .= implode(',', $valuesArr);


$update = mysql_query($sql);
}

?>

但是 var_dump($sql);显示:

string(443) "INSERT INTO data (id, coinname, cointag, algorithm, difficulty, blockreward, blockcount, profitratio, avgprofitratio, exchange, exchangerate, exchangevolume, isblockexploreronline, isexchangeonline, message, blocktimeinseconds, healthstatus, datetime) values ('', '', '','','','','','','','','', '','','','', NOW()),('', '9', '9','9','9','9','9','9','9','9','9', '9','9','9','9', NOW()),('', '', '','','','','','','','','', '','','','', NOW())"

我的错误是什么？

Answer 1

您走在正确的轨道上。

foreach($json_array as $apiData){
  //mysql mapping
}

在这种情况下，mysql 映射是将不同值(例如:$apiData[CoinName])映射到特定行的方式。

对于更大的结果，这可能会导致加载时间过长。所以也许你应该看看，你不要一次做太多。大多数 API 都取悦于您，只获取您的任务真正需要的数据。如果这些是一般的游戏数据库信息，请执行一次性导入脚本来存储它们。那么花多长时间并不重要。因为您作为管理员只插入一次。