Possible Duplicate:
Updating progress dialog in Activity from AsyncTask
我正在开发我的第一个 Android 应用程序,我需要在后台任务(在本例中只是服务器上的 http 调用)发生时显示 ProgressDialog。 我对此进行了一些研究,并且已经检查了与该主题相关的其他线程。
http://developer.android.com/reference/android/os/AsyncTask.html
Android show ProgressDialog until activity UI finished loading
http://android-developers.blogspot.com/2009/05/painless-threading.html
等等。
比我写一点代码:
1) 在我的 Activity 中,我声明一个变量为 ProgressDialog 类型
public class LoginActivity extends Activity {
public static final String TAG = "LoginActivity";
protected ProgressDialog progressDialog;
...
2) 我还编写了一个内部类来根据需要扩展 AsyncTask,在 doInBackGround 中我调用了一个静态方法,该方法实际上向服务器执行 POST http 请求,在服务器端我阻止了服务器响应20 秒验证进度对话框。
class EfetuaLogin extends AsyncTask<Object, Void, String> {
private final static String TAG = "LoginActivity.EfetuaLogin";
@Override
protected void onPreExecute()
{
Log.d(TAG, "Executando onPreExecute de EfetuaLogin");
}
@SuppressWarnings("unchecked")
@Override
protected String doInBackground(Object... parametros) {
Log.d(TAG, "Executando doInBackground de EfetuaLogin");
Object[] params = parametros;
HttpClient httpClient = (HttpClient) params[0];
List<NameValuePair> listaParametros = (List<NameValuePair>) params[1];
String result = null;
try{
result = HttpProxy.httpPost(AnototudoMetadata.URL_AUTENTICACAO, httpClient, listaParametros);
}catch (IOException e) {
Log.e(TAG, "IOException, Sem conectividade com o servidor do Anototudo! " + e.getMessage());
e.printStackTrace();
return result;
}
return result;
}
@Override
protected void onPostExecute(String result)
{
progressDialog.dismiss();
}
}
3)当按下按钮时,我会构建 ProgressDialog 并调用我创建的 AsyncTask:
OnClickListener loginListener = new OnClickListener() {
public void onClick(View v) {
//next line should start progress dialog in main thread ?????
progressDialog = ProgressDialog.show(LoginActivity.this, "Login in", "Wait a moment please", true, false);
//next couple of lines should do an ascyn call to server
EfetuaLogin efetuaLogin = new EfetuaLogin();
efetuaLogin.execute(params);
try {
//recover the server response and sets time out to be 25seconds
sResposta = efetuaLogin.get(25, TimeUnit.SECONDS);
好吧,就是这样,我相信这是假设显示一个进度对话框,而 AsyncTask 将在后台查询服务器,但我得到的是在服务器响应到达之前没有进度条,而不是一小部分时间(更少超过 1 秒)进度显示并调用下一个 Activity。
正如我所提到的,我已经重新检查了这段代码,但根本找不到我出错的地方。 有什么建议吗?
提前谢谢你。
嗨,正如 Charlie Sheen(???) 在该线程的第一个答案中所建议的那样,我尝试更改了一些代码,现在它就像(不幸的是,到目前为止它没有按预期工作):
OnClickListener loginListener = new OnClickListener() {
public void onClick(View v) {
//async call????????
new EfetuaLogin().execute(params);
...
然后在 AsyncTask 中完成所有处理响应的工作:
class EfetuaLogin extends AsyncTask<Object, Void, String> {
private final static String TAG = "LoginActivity.EfetuaLogin";
@Override
protected void onPreExecute()
{
super.onPreExecute();
Log.d(TAG, "Executando onPreExecute de EfetuaLogin");
//inicia diálogo de progresso, mostranto processamento com servidor.
progressDialog = ProgressDialog.show(LoginActivity.this, "Autenticando", "Contactando o servidor, por favor, aguarde alguns instantes.", true, false);
}
@SuppressWarnings("unchecked")
@Override
protected String doInBackground(Object... parametros) {
Log.d(TAG, "Executando doInBackground de EfetuaLogin");
Object[] params = parametros;
HttpClient httpClient = (HttpClient) params[0];
List<NameValuePair> listaParametros = (List<NameValuePair>) params[1];
String result = null;
try{
result = HttpProxy.httpPost(AnototudoMetadata.URL_AUTENTICACAO, httpClient, listaParametros);
}catch (IOException e) {
Log.e(TAG, "IOException, Sem conectividade com o servidor do Anototudo! " + e.getMessage());
e.printStackTrace();
return result;
}
return result;
}
@Override
protected void onPostExecute(String result)
{
super.onPostExecute(result);
if (result == null || result.equals("")) {
progressDialog.dismiss();
Alerta
.popupAlertaComBotaoOK(
"Dados incorretos",
"Os dados informados não foram encontrados no Sistema! Informe novamente ou cadastre-se antes pela internet.",
LoginActivity.this);
return;
}
Log.d(TAG, "Login passou persistindo info de login local no device");
ContentValues contentValues = new ContentValues();
contentValues.put(AnototudoMetadata.LOGIN_EMAIL, sLogin);
contentValues.put(AnototudoMetadata.LOGIN_SENHA, sSenha);
contentValues.put(AnototudoMetadata.LOGIN_SENHA_GERADA, result);
LoginDB loginDB = new LoginDB();
loginDB.addLogin(LoginActivity.this, contentValues);
Log.d(TAG, "Persistiu info de login no device, redirecionando para menu principal do Anototudo");
Log.d(TAG, "O retorno da chamada foi ==>> " + result);
// tudo ok chama menu principal
Log.d(TAG, "Device foi corretametne autenticado, chamando tela do menu principal do Anototudo.");
String actionName = "br.com.anototudo.intent.action.MainMenuView";
Intent intent = new Intent(actionName);
LoginActivity.this.startActivity(intent);
progressDialog.dismiss();
}
}
完成 OnClickListener:
OnClickListener loginListener = new OnClickListener() {
public void onClick(View v) {
Log.d(TAG, "Usuario logado, chamando menu principal");
TextView tLogin = (TextView) findViewById(R.id.loginText);
TextView tSenha = (TextView) findViewById(R.id.senhaText);
String sLogin = tLogin.getText().toString();
String sSenha = tSenha.getText().toString();
if (sLogin.equals("") | sSenha.equals("")) {
Alerta.popupAlertaComBotaoOK("Campos Obrigatórios",
"Os campos Login e Senha são obrigatórios para autenticação do Anototudo.", LoginActivity.this);
return;
} else {
Pattern regEx = Pattern.compile(".+@.+\\.[a-z]+");
Matcher matcher = regEx.matcher(sLogin);
if (!matcher.matches()) {
Alerta.popupAlertaComBotaoOK("Formato e-mail inválido", "O formato do campo e-mail está inválido",
LoginActivity.this);
return;
}
}
List<NameValuePair> listaParametros = new ArrayList<NameValuePair>();
listaParametros.add(new BasicNameValuePair("login", sLogin));
listaParametros.add(new BasicNameValuePair("senha", sSenha));
Log.d(TAG, "valores recuperados dos campos de login e senha: " + sLogin + " | " + sSenha);
// Reutiliza cliente HttpClient disponibilizado pela Aplicação.
AnototudoApp atapp = (AnototudoApp) LoginActivity.this.getApplication();
HttpClient httpClient = atapp.getHttpClient();
//prepara lista de parametros para fazer chamada asíncrona no servidor para autenticar.
Object[] params = new Object[2];
params[0] = httpClient;
params[1] = listaParametros;
//faz chamada assincrona
new EfetuaLogin().execute(params);
}
};
最佳答案
将你的 ProgressDialog
放在 onPreExecute
中,示例代码如下:
private ProgressDialog pdia;
@Override
protected void onPreExecute(){
super.onPreExecute();
pdia = new ProgressDialog(yourContext);
pdia.setMessage("Loading...");
pdia.show();
}
@Override
protected void onPostExecute(String result){
super.onPostExecute(result);
pdia.dismiss();
}
在您的 onClickListener
中,只需将这一行放在里面:
new EfetuaLogin().execute(null, null , null);
关于android - 如何在 Android 中进行后台工作时使用 AsyncTask 显示 ProgressDialog?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3893626/