我在 SO 上搜索了一下,没能找到这个独特的用例,但也许我不知道如何表达它。我希望使用 PHP 数组(请参阅下面的格式)构建一个动态 HTML 菜单,当存在匹配项时将相同的字符串值复制到子菜单中。
这可能太复杂了,但我想知道是否可行,以及是否有人有代码示例。 我不介意更改“verse”数组值结构以使其更加可变并使其正常工作(可能将其转换为数组,因为其中有 1:many 潜在值。) p>
我无法让下面的 HTML 格式非常适合 SO,但请求的要点是所有具有匹配书籍/章节字符串的文章都将放在一起并嵌套。如果诗篇 121 有 2 个条目(在下面的数组中),那么它们应该嵌套在同一个子菜单中。
所需的结束结构(请注意,因为 2 个字符串与诗篇第 121 章匹配,所以它们组合在一起:
Hebrews
Chapter 12
Verse 26-28
Chapter 9
Verse 23-24
Psalms
Chapter 121
Verse 3-4
Verse 7-10
Chapter 16
Verse 11
Exodus
Chapter 33
Verse 14
预先感谢您的帮助!
PHP 数组:
<?php
$articles = array(
array(
'contentid' => '109',
'full' => 'Song by Artist (Ref 109)',
'verse' => 'Hebrews 12:26-28'),
array(
'contentid' => '110',
'full' => 'Song by Artist (Ref 110)',
'verse' => 'Psalms 121:3-4'),
array(
'contentid' => '111',
'full' => 'Song by Artist (Ref 111)',
'verse' => 'Hebrews 9:23-24'),
array(
'contentid' => '112',
'full' => 'Song by Artist (Ref 112)',
'verse' => 'Psalms 16:11; Exodus 33:14; Psalms 121:7-10'));
?>
我想绘制一个如下所示的 HTML 菜单:
<!-- Hebrews -->
<div class="submenu">
<a href="#">**Hebrews**</a>
<!-- Level 2 menu -->
<div>
<div>
<div class="submenu">
<a href="#">Chapter *12*</a>
<!-- Level 3 menu -->
<div>
<div>
<a href="#"><span>Song by Artist (Ref 109)</span>Verse *26-28*</a>
</div>
</div>
</div>
<div class="submenu">
<a href="#">Chapter *9*</a>
<!-- Level 3 menu -->
<div>
<div>
<a href="#"><span>Song by Artist (Ref 111)</span>Verse *23-24*</a>
</div>
</div>
</div>
<!-- Psalms -->
<div class="submenu">
<a href="#">**Psalms**</a>
<!-- Level 2 menu -->
<div>
<div>
<div class="submenu">
<a href="#">Chapter *121*</a>
<!-- Level 3 menu -->
<div>
<div>
<a href="#"><span>Song by Artist (Ref 110)</span>Verse *3-4*</a>
<a href="#"><span>Song by Artist (Ref 112)</span>Verse *7-10*</a> </div>
</div>
</div>
第*9章*
艺术家的歌曲 (Ref 111)Verse *23-24*
最佳答案
$articles = array
(
array
(
'contentid' => '109',
'full' => 'Song by Artist (Ref 109)',
'verse' => 'Hebrews 12:26-28'
),
array
(
'contentid' => '110',
'full' => 'Song by Artist (Ref 110)',
'verse' => 'Psalms 121:3-4'
),
array
(
'contentid' => '111',
'full' => 'Song by Artist (Ref 111)',
'verse' => 'Hebrews 9:23-24; Psalms 121:3-4'
),
array
(
'contentid' => '112',
'full' => 'Song by Artist (Ref 112)',
'verse' => 'Psalms 16:11; Exodus 33:14; Psalms 121:7-10; Psalms 121:3-4'
)
);
$langs = array();
foreach($articles as $article)
{
foreach(explode("; ", $article["verse"]) as $verseData)
{
$verse = explode(" ", $verseData);
$lang = $verse[0];
$fullVerse = $verse[1];
$verse = explode(":", $verse[1]);
$chapter = $verse[0];
if(empty($langs[$lang]))
$langs[$lang] = array();
if(empty($langs[$lang][$fullVerse]))
$langs[$lang][$fullVerse] = array();
$langs[$lang][$fullVerse][] = array
(
"full" => $article["full"]
);
}
}
foreach($langs as $lang => $data)
{
generateHtml($lang, $data);
}
function generateHtml($lang, $data)
{
echo "<!-- ". $lang ." -->\n";
echo "<div class=\"submenu\">\n";
echo "<a href=\"#\">**". $lang ."**</a>\n";
echo "<!-- Level 2 menu -->\n";
echo "<div>\n";
echo "<div>\n";
foreach($data as $fullVerse => $verses)
{
$verse = explode(":", $fullVerse);
$chapter = $verse[0];
$verse = $verse[1];
echo "<div class=\"submenu\">\n";
echo "<a href=\"#\">Chapter *". $chapter ."*</a>\n";
echo "<!-- Level 3 menu -->\n";
echo "<div>\n";
echo "<div>\n";
foreach($verses as $verseIndex => $value)
{
if(count($verses) > 1)
$value["full"] .= " (". ($verseIndex + 1) .")";
echo "<a href=\"#\"><span>". $value["full"] ."</span>Verse *". $verse ."*</a>\n";
}
echo "</div>\n";
echo "</div>\n";
}
echo "</div>\n";
echo "</div>\n";
echo "</div>\n";
}
您还可以使用 \t
添加制表符空间。
我的建议是如果你已经像这样生成它。通过删除所有 \n
使其成为一行。
关于PHP - 从基于值名称组合类似值的 php 数组构建多级 HTML 菜单,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30144028/