php:对给定字符串中的单词实例进行排序和计数

Question

我需要帮助对字符串中的单词实例进行排序和计数。

假设我有一个单词集:

happy beautiful happy lines pear gin happy lines rock happy lines pear

我如何使用 php 来计算字符串中每个单词的每个实例并在循环中输出它:

There are $count instances of $word

这样上面的循环会输出:

There are 4 instances of happy.

There are 3 instances of lines.

There are 2 instances of gin....

Answer 1

使用 str_word_count() 的组合和 array_count_values() :

$str = 'happy beautiful happy lines pear gin happy lines rock happy lines pear ';
$words = array_count_values(str_word_count($str, 1));
print_r($words);

给予

Array
(
    [happy] => 4
    [beautiful] => 1
    [lines] => 3
    [pear] => 2
    [gin] => 1
    [rock] => 1
)

str_word_count() 中的 1 使函数返回所有找到的单词的数组。

要对条目进行排序，请使用 arsort() (它保留 key ):

arsort($words);
print_r($words);

Array
(
    [happy] => 4
    [lines] => 3
    [pear] => 2
    [rock] => 1
    [gin] => 1
    [beautiful] => 1
)