PHP 匹配一个字符串

Question

我有一个印度公司数据集，需要从地址字段中提取城市和邮政编码:

地址字段示例: Gowripuram West, Sengunthapuram Post, Near L.G.B., Karur, Tamilnadu, Karur - 639 002, 印度

如您所见，城市是 Karur，zip 紧跟在 -(连字符)之后。

我需要 PHP 代码来匹配 [city] - [zip]

不确定如何执行此操作我可以在 Hypen 之后找到 Zip 但不确定如何找到城市，请注意城市可以是 2 个单词。

为你的时间干杯。/

J

Answer 1

试试这个:

<?php
$address = "Gowripuram West, Sengunthapuram Post, Near L.G.B., Karur, Tamilnadu, Karur - 639 002, India";

// removes spaces between digits.
$address = preg_replace('{(\d)\s+(\d)}','\1\2',$address);

// removes spaces surrounding comma.
$address = preg_replace('{\s*,\s*}',',',$address);
var_dump($address);

// zip is 6 digit number and city is the word(s) appearing betwwen zip and previous comma.
if(preg_match('@.*,(.*?)(\d{6})@',$address,$matches)) {
    $city = trim($matches[1]);
    $zip = trim($matches[2]);
}

$city = preg_replace('{\W+$}','',$city);

var_dump($city);    // prints Karur
var_dump($zip);     // prints 639002

?>