javascript - 获取选定的选项 jquery on change 函数不起作用

Question

当我选择下拉选项时，不会在隐藏字段中分配所选选项的值。

请纠正我做错的地方。提前致谢。

<?php 
include("../common/config.php");

$time = time();
$id=$_REQUEST['dr_id'];

$allEst = $db->select(array("*"),PREFIX."obligation_pharmacy","obligation_id IN ($id)");
    }
  ?>

<script type="text/javascript">
function populate(unique,sel){
alert(sel.value);
$("#pharmacy_id"+unique).val(sel.value);
}
</script>

   <select name="pharmacy_name[]" class="name" id="pharmacy_name<?php echo $time?>" style="width:180px; font-size:11px;" onchange="populate(<?php echo $time?>,this)">
   <option value="">Select Pharmacy Name</option>
   <?php
      foreach($allEst as $ss)
        {if($ss->pharmacy_name!=''){?>
         <option value="<?php echo $ss->id;?>"><?php echo $ss->pharmacy_name; ?></option>
        <?php }} ?>  

  </select>
     <input type="hidden" name="pharmacy_id[]" id="pharmacy_id<?php echo $time?>" value=""> 

Answer 1

使用 jQuery，通常是这样的:

$('#my-select').change(function(){
    var value = $(this).val();
    $('#my-hidden-input').val(value);
});