php - 如何限制用户访问 YII 框架中的个人资料信息

Question

如何限制用户对他人信息的访问。

我已经为用户尝试过 Controller ，他们可以访问其他用户的 Controller 索引。请描述如何更改 YII 框架中的设置，使每个用户只能访问他们的信息。

我使用的是 1.1.X 版本

我又来了，我有我以前的问题 我希望他们只看到他们的笔记

<?php

class TextController extends Controller
{
    /**
     * @var string the default layout for the views. Defaults to '//layouts/column2', meaning
     * using two-column layout. See 'protected/views/layouts/column2.php'.
     */
    public $layout='//layouts/column2';

    /**
     * @return array action filters
     */
    public function filters()
    {
        return array(
            'accessControl', // perform access control for CRUD operations
            'postOnly + delete', // we only allow deletion via POST request
        );
    }

    /**
     * Specifies the access control rules.
     * This method is used by the 'accessControl' filter.
     * @return array access control rules
     */
    public function accessRules()
    {
        return array(
            array('allow',  // allow all users to perform 'index' and 'view' actions
                'actions'=>array('index','view'),
                'users'=>array('*'),
            ),
            array('allow', // allow authenticated user to perform 'create' and 'update' actions
                'actions'=>array('create','update'),
                'users'=>array('@'),
            ),
            array('allow', // allow admin user to perform 'admin' and 'delete' actions
                'actions'=>array('admin','delete'),
                'users'=>array('admin'),
            ),
            array('deny',  // deny all users
                'users'=>array('*'),
            ),
        );
    }

    /**
     * Displays a particular model.
     * @param integer $id the ID of the model to be displayed
     */
    public function actionView($id)
    {
        $this->render('view',array(
            'model'=>$this->loadModel($id),
        ));
    }

    /**
     * Creates a new model.
     * If creation is successful, the browser will be redirected to the 'view' page.
     */
    public function actionCreate()
    {
        $model=new Text;

        // Uncomment the following line if AJAX validation is needed
        // $this->performAjaxValidation($model);

        if(isset($_POST['Text']))
        {
            $model->attributes=$_POST['Text'];
            if($model->save())
                $this->redirect(array('view','id'=>$model->id));
        }

        $this->render('create',array(
            'model'=>$model,
        ));
    }

    /**
     * Updates a particular model.
     * If update is successful, the browser will be redirected to the 'view' page.
     * @param integer $id the ID of the model to be updated
     */
    public function actionUpdate($id)
    {
        $model=$this->loadModel($id);

        // Uncomment the following line if AJAX validation is needed
        // $this->performAjaxValidation($model);

        if(isset($_POST['Text']))
        {
            $model->attributes=$_POST['Text'];
            if($model->save())
                $this->redirect(array('view','id'=>$model->id));
        }

        $this->render('update',array(
            'model'=>$model,
        ));
    }

    /**
     * Deletes a particular model.
     * If deletion is successful, the browser will be redirected to the 'admin' page.
     * @param integer $id the ID of the model to be deleted
     */
    public function actionDelete($id)
    {
        $this->loadModel($id)->delete();

        // if AJAX request (triggered by deletion via admin grid view), we should not redirect the browser
        if(!isset($_GET['ajax']))
            $this->redirect(isset($_POST['returnUrl']) ? $_POST['returnUrl'] : array('admin'));
    }

    /**
     * Lists all models.
     */
    public function actionIndex()
    {
        $dataProvider=new CActiveDataProvider('Text');
        $this->render('index',array(
            'dataProvider'=>$dataProvider,
        ));
    }

    /**
     * Manages all models.
     */
    public function actionAdmin()
    {
        $model=new Text('search');
        $model->unsetAttributes();  // clear any default values
        if(isset($_GET['Text']))
            $model->attributes=$_GET['Text'];

        $this->render('admin',array(
            'model'=>$model,
        ));
    }

    /**
     * Returns the data model based on the primary key given in the GET variable.
     * If the data model is not found, an HTTP exception will be raised.
     * @param integer $id the ID of the model to be loaded
     * @return Text the loaded model
     * @throws CHttpException
     */
    public function loadModel($id)
    {
        $model=Text::model()->findByPk($id);
        if($model===null)
            throw new CHttpException(404,'The requested page does not exist.');
        return $model;
    }

    /**
     * Performs the AJAX validation.
     * @param Text $model the model to be validated
     */
    protected function performAjaxValidation($model)
    {
        if(isset($_POST['ajax']) && $_POST['ajax']==='text-form')
        {
            echo CActiveForm::validate($model);
            Yii::app()->end();
        }
    }
}

显示的限制已解决。但是用户通过URL可以访问别人做的笔记要做到这一点，给那个人可以更改top number然后他就可以访问其他用户的信息对于这个问题我该怎么办？

Answer 1

你需要在你的dataprovider中添加条件如下(确保数据库中的字段名是user_id，如果不是，你需要在snippet中修改)

  public function actionIndex()
{
    $dataProvider=new CActiveDataProvider('Text',array(
        'criteria' => array(
            'condition' => 'user_id=:user_id',
            'params' => array(':user_id' => Yii::app()->User->id),);
    $this->render('index',array(
        'dataProvider'=>$dataProvider,
    ));
}