我已经在我的数据库查询上构建了一个过滤器,现在 我想让它更舒适。 目标是让它变得动态,这意味着 用户可以选择任意组合。
public function filter(FilterList $request)
{
$view = view('profile.browse.list');
$search = $request->get('filter');
$filter = [
'male' => Profile::male(),
'female' => Profile::female(),
'10' => Profile::man(),
'11' => Profile::women(),
'12' => Profile::couple(),
'15' => Profile::domina(),
'20' => Profile::affaire(),
'21' => Profile::cybersex(),
'22' => Profile::marriage(),
'23' => Profile::flirt(),
];
return $view->with([
'List' => $filter[$search]->unmoderated()->paginate(15)->appends(['filter' => $search]),
]);
}
我知道我的解决方案并不是一个很好的解决方案。 我已将查询范围保存在 $filter 数组中,并且 不能像这样添加第二个或第三个范围
$users = User::popular()->women()->orderBy('created_at')->get();
http://laravel.com/docs/5.0/eloquent#query-scopes
有任何提示可以让我做得更好。
我不知道要开始...
感谢您的帮助
编辑
public function scopeMarriage($query)
{
return $query->where('LookFor', 'LIKE', '%Ehe%');
}
最佳答案
因此,用户正在提交动态数量的输入,并且基于这些输入,您想将查询范围链接到您的查询吗?如果那是你想要的,我相信你可以这样做:
// Method array taken from your example
$methods = [
'male' => 'male',
'female' => 'female',
'12' => 'couple',
];
// Begin the query. Since the unmoderated() scope query is always called,
// I used that in this example.
// But note that you can also use Model::query(); to begin a query
$query = Profile::unmoderated();
// Loop through the request inputs
foreach ($request->all() as $param)
{
// If it exists in the provided array, add it to the query.
if (array_key_exists($param, $methods))
{
$query->{$methods[$param]}();
}
}
// Call get, paginate, etc. to actually fetch the results and then return it.
return $query->paginate(15);
关于php - 多个动态查询范围,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33367128/