我正在编写一个小文件上传实用程序,作为一个更大项目的一部分。最初我是使用 Apache commons File 实用程序类从 servlet 处理这个问题。这是我为该服务编写的快速测试客户端的片段:
public static void main(String[] args) {
JaxWsProxyFactoryBean factory = new JaxWsProxyFactoryBean();
factory.getInInterceptors().add(new LoggingInInterceptor());
factory.getOutInterceptors().add(new LoggingOutInterceptor());
factory.setServiceClass(FileUploadService.class);
factory.setAddress("http://localhost:8080/FileUploadService/FileUploadService");
FileUploadService client = (FileUploadService) factory.create();
FileType file = new FileType();
file.setName("statemo_1256144312279");
file.setType("xls");
DataSource source = new FileDataSource(new File("c:/development/statemo_1256144312279.xls"));
file.setHandler(new DataHandler(source));
Boolean ret = client.uploadFile(file);
System.out.println (ret);
System.exit(0);
这绝对没问题。现在,当我试图替换 Apache 公共(public)实用程序时,问题就来了。在上面的代码中,我从一个具有绝对路径名的文件创建了一个数据源。在我的 servlet 中,我无法获得绝对路径名,而且我通过线路发送的文件是空的。
这是 servlet 代码:
@SuppressWarnings("unchecked")
protected void doPost (final HttpServletRequest request, final HttpServletResponse response)
throws ServletException, IOException {
// form should have enctype="multipart/form-data" as an attribute
if (!ServletFileUpload.isMultipartContent (request)) {
LOG.info("Invalid form attribute");
return;
}
//DataInputStream in = new DataInputStream(request.getInputStream());
final DiskFileItemFactory factory = new DiskFileItemFactory ();
factory.setSizeThreshold(FILE_THRESHOLD_SIZE);
final ServletFileUpload sfu = new ServletFileUpload (factory);
sfu.setSizeMax(MAX_FILE_SIZE);
final HttpSession session = request.getSession();
final List<FileItem> files = new ArrayList<FileItem>();
final List<String> filesToProcess = new ArrayList<String>();
try {
final List<FileItem> items = sfu.parseRequest(request);
for (final FileItem f : items) {
if (!f.isFormField())
files.add(f);
}
/*for (final FileItem f : files) {
final String absoluteFileName = UPLOAD_DESTINATION + FilenameUtils.getName(f.getName());
//f.write(new File (absoluteFileName));
filesToProcess.add(absoluteFileName);
}*/
FileItem f = files.get(0);
LOG.info("File: " + FilenameUtils.getName(f.getName()));
LOG.info("FileBaseName: " + FilenameUtils.getBaseName(f.getName()));
LOG.info("FileExtension: " + FilenameUtils.getExtension(f.getName()));
FileUploadServiceClient client = new FileUploadServiceClient();
DataSource source = new FileDataSource(new File(f.getName()));
FileType file = new FileType();
file.setHandler(new DataHandler(source));
file.setName(FilenameUtils.getBaseName(f.getName()));
file.setType(FilenameUtils.getExtension(f.getName()));
Boolean ret = client.uploadFile(file);
LOG.info("File uploaded - " + ret);
filesToProcess.add(UPLOAD_DESTINATION + FilenameUtils.getName(f.getName()));
session.setAttribute("filesToProcess", filesToProcess);
final RequestDispatcher dispatcher = request.getRequestDispatcher("Validate");
if (null != dispatcher) {
dispatcher.forward(request, response);
}
} catch (FileUploadException e) {
LOG.info("Exception " + e.getMessage());
e.printStackTrace();
} catch (Exception e) {
LOG.info("Exception " + e.getMessage());
e.printStackTrace();
}
我今天上午的大部分时间都在处理这个问题,但一无所获。即使我完全摆脱 Apache 公共(public)文件的东西并自己处理请求的解析,我仍然无法适本地构建数据源。
谢谢!
最佳答案
这实际上很简单,我只是将字节从 InputStream 复制到 DataSource:
FileItem f = files.get(0);
// there is a problem here where the file being created is empty, since we only have a
// partial path:
DataSource source = new FileDataSource(new File(f.getName()));
// because of the above problem, we are going to copy over the data ourselves:
byte[] sourceBytes = f.get();
OutputStream sourceOS = source.getOutputStream();
sourceOS.write(sourceBytes);
关于java - 从 InputStream 或 Byte 数组构造 DataSource,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2141829/