Java正则表达式分别匹配每个组

Question

我有这样一个字符串:

String text = "new SingleSizeProduct(422056, 1265858, 5430, '3XL', 75, 0, '14.90',     '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265859, 5341, 'L', 55, 0, '14.90',     '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265860, 5459, 'M', 45, 1, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265861, 5446, 'S', 35, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265862, 5458, 'XL', 60, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265863, 5511, 'XXL', 65, 0, '14.90', '16.50', '29.90', 'TL')";

和正则表达式:

String regex = "new SingleSizeProduct((.*))";

我想分别匹配所有 6 个组，但是当我匹配模式时，我得到这样的结果:

(
[0] => new SingleSizeProduct(422056, 1265858, 5430, '3XL', 75, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265859, 5341, 'L', 55, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265860, 5459, 'M', 45, 1, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265861, 5446, 'S', 35, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265862, 5458, 'XL', 60, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265863, 5511, 'XXL', 65, 0, '14.90', '16.50', '29.90', 'TL'),
[1] => (422056, 1265858, 5430, '3XL', 75, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265859, 5341, 'L', 55, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265860, 5459, 'M', 45, 1, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265861, 5446, 'S', 35, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265862, 5458, 'XL', 60, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265863, 5511, 'XXL', 65, 0, '14.90', '16.50', '29.90', 'TL'),
[2] => (422056, 1265858, 5430, '3XL', 75, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265859, 5341, 'L', 55, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265860, 5459, 'M', 45, 1, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265861, 5446, 'S', 35, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265862, 5458, 'XL', 60, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265863, 5511, 'XXL', 65, 0, '14.90', '16.50', '29.90', 'TL'),
)

如何分别匹配每个组？

Answer 1

.* 是贪婪的，所以它会尝试找到最大可能的匹配，这意味着 (.*) 将匹配

abc(foo)def(bar)ghi
    ^^^^^^^^^^^

如果你想让它找到最小可能的匹配

abc(foo)def(bar)ghi
    ^^^     ^^^

通过在 ? 之后添加 * 不情愿

String regex = "new SingleSizeProduct((.*?))";

您还需要转义 ( 和 ) 因为正如您所知，它们代表捕获组的开始和结束。

String regex = "new SingleSizeProduct\\((.*?)\\)";

顺便说一句。另一种解决方案是使用 .*? [^)]* 代替，这意味着，除 )

之外的所有内容

String regex = "new SingleSizeProduct(([^)]*))";