我的两个 toString() 似乎处于无限循环中,但我不确定问题出在哪里。我已经调试了几个小时,看不出有什么问题。
对于上下文,主要的相关部分是: System.out.println(class1); adminStaff1.assignInstructor(class1, instructor1); System.out.println(class1);
第一个 println 有效,但是当我调试时,我在它通过之前看到一个源查找错误。第二个 class1 创建 StackOverflowError 是:
Exception in thread "main" java.lang.StackOverflowError
at java.lang.AbstractStringBuilder.append(Unknown Source)
at java.lang.StringBuilder.append(Unknown Source)
at java.lang.StringBuilder.<init>(Unknown Source)
at Instructor.toString(Instructor.java:59)
at java.lang.String.valueOf(Unknown Source)
at java.lang.StringBuilder.append(Unknown Source)
at Class.toString(Class.java:89)
at java.lang.String.valueOf(Unknown Source)
at java.lang.StringBuilder.append(Unknown Source)
at java.util.AbstractCollection.toString(Unknown Source)
at java.lang.String.valueOf(Unknown Source)
at java.lang.StringBuilder.append(Unknown Source)
at Instructor.toString(Instructor.java:59)
类的 toString 是:
@Override
public String toString() {
return "Class [instructor=" + instructor + ", lectureHall="
+ lectureHall + ", currentEnrollment=" + currentEnrollment
+ ", timeSlot=" + timeSlot + ", filled=" + filled
+ ", studentList=" + studentList + "]";
}
Instructor 的 toString 是:
@Override
public String toString() {
return "Instructor [salary=" + salary + ", classList=" + classList
+ ", openTimeSlots=" + openTimeSlots + ", "
+ super.toString() + "]";
}
super.toString() 是:
@Override
public String toString() {
return "[idNumber=" + idNumber + ", email=" + email
+ "]";
}
我不确定为什么,但 adminStaff1.assignInstructor 似乎也导致了这个问题,它是:
public void enrollStudent(Student student, Class aClass){
aClass.checkIfFilled();
if(!aClass.getFilled()){
aClass.addStudent(student);
student.addClass(aClass);
aClass.increaseEnrollment();
} else {
System.out.println("Could not add student because the class is currently full.");
}
}
如果有人能帮助我理解问题所在,我将不胜感激。谢谢。
最佳答案
当您在 Class
上调用 toString()
时,它包括 Instructor
(而 Instructor
包括类
)。这是一个循环。打破它,要么
return "Instructor [salary=" + salary + /* ", classList=" + classList */
+ ", openTimeSlots=" + openTimeSlots + ", "
+ super.toString() + "]";
或者,
return "Class [lectureHall=" + lectureHall + ", currentEnrollment="
+ currentEnrollment + ", timeSlot=" + timeSlot + ", filled=" + filled
+ ", studentList=" + studentList + "]";
关于java - toStrings() 的堆栈溢出错误 (java),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26541775/