我想在 ScheduledExecutorService
上模拟一个电话返回 ScheduledFuture
的模拟类时方法 schedule
被调用。以下代码编译并正常工作:
ScheduledExecutorService executor = Mockito.mock(ScheduledExecutorService.class);
ScheduledFuture future = Mockito.mock(ScheduledFuture.class);
Mockito.when(executor.schedule(
Mockito.any(Runnable.class),
Mockito.anyLong(),
Mockito.any(TimeUnit.class))
).thenReturn(future); // <-- warning here
除了我在最后一行收到未经检查的警告:
found raw type: java.util.concurrent.ScheduledFuture
missing type arguments for generic class java.util.concurrent.ScheduledFuture<V>
unchecked method invocation: method thenReturn in interface org.mockito.stubbing.OngoingStubbing is applied to given types
required: T
found: java.util.concurrent.ScheduledFuture
unchecked conversion
required: T
found: java.util.concurrent.ScheduledFuture
是否有可能以某种方式避免这些警告?
代码类似于 ScheduledFuture<?> future = Mockito.mock(ScheduledFuture.class);
不编译。
最佳答案
当使用模拟规范的替代方式时,所有警告都会消失:
ScheduledFuture<?> future = Mockito.mock(ScheduledFuture.class);
Mockito.doReturn(future).when(executor).schedule(
Mockito.any(Runnable.class),
Mockito.anyLong(),
Mockito.any(TimeUnit.class)
);
关于java - 使用 Mockito 时避免未经检查的警告,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34475010/