我想创建一个使用 lambda 表达式应用通用统计信息的简单类。 我想知道如何避免在 statistic() 方法中使用 switch case?
例如,我可能想写一个新的lambda来计算列表的方差等。
谢谢。
public class DescriptiveStatistics {
public static void main(String[] args) {
List<Double> numbers = Arrays.asList(1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0);
numbers.stream().forEach(n-> System.out.print(n + " "));
System.out.println();
System.out.println("Descriptive statistics");
System.out.println("Sum: " + statistic(numbers, "Sum"));
System.out.println("Max: " + statistic(numbers, "Max"));
System.out.println("Min: " + statistic(numbers, "Min"));
System.out.println("Average: " + statistic(numbers, "Average"));
System.out.println("Count: " + statistic(numbers, "Count"));
}
private static double statistic(List<Double> numbers, String function) {
switch (function.toLowerCase()) {
case "sum":
return numbers.stream().mapToDouble(Double::doubleValue).sum();
case "max":
return numbers.stream().mapToDouble(Double::doubleValue).max().getAsDouble();
case "min":
return numbers.stream().mapToDouble(Double::doubleValue).min().getAsDouble();
case "average":
return numbers.stream().mapToDouble(Double::doubleValue).average().getAsDouble();
case "count":
return numbers.stream().mapToDouble(Double::doubleValue).count();
}
return 0;
}
我想到了这样的方法
private static double newStatistics(List<Double> numbers, Function<Double, Double> function){
return numbers.stream().mapToDouble(Double::doubleValue).function();
}
最佳答案
为什么不简单地使用 DoubleStream#summaryStatistics或应用类似的模式?
您甚至可以扩展该类以添加自定义方法,例如方差、偏度和峰度:
/**
* Algorithms derived from: Philippe Pébay, Formulas for Robust, One-Pass Parallel
* Computation of Covariances and Arbitrary-Order Statistical Moments.
*/
public class MoreDoubleStatistics extends DoubleSummaryStatistics {
private double M1, M2, M3, M4;
@Override
public void accept(double x) {
super.accept(x);
long n = getCount();
double delta = x - M1; // δ
double delta_n = delta / n; // δ / n
double delta2_n = delta * delta_n; // δ^2 / n
double delta2_n2 = delta_n * delta_n; // δ^2 / n^2
double delta3_n2 = delta2_n * delta_n; // δ^3 / n^2
double delta4_n3 = delta3_n2 * delta_n; // δ^4 / n^3
M4 += (n - 1) * (n * n - 3 * n + 3) * delta4_n3
+ 6 * M2 * delta2_n2
- 4 * M3 * delta_n;
M3 += (n - 1) * (n - 2) * delta3_n2
- 3 * M2 * delta_n;
M2 += (n - 1) * delta2_n;
M1 += delta_n;
}
@Override
public void combine(DoubleSummaryStatistics other) {
throw new UnsupportedOperationException(
"Can't combine a standard DoubleSummaryStatistics with this class");
}
public void combine(MoreDoubleStatistics other) {
MoreDoubleStatistics s1 = this;
MoreDoubleStatistics s2 = other;
long n1 = s1.n();
long n2 = s2.n();
long n = n1 + n2;
double delta = s2.M1 - s1.M1; // δ
double delta_n = delta / n; // δ / n
double delta2_n = delta * delta_n; // δ^2 / n
double delta2_n2 = delta_n * delta_n; // δ^2 / n^2
double delta3_n2 = delta2_n * delta_n; // δ^3 / n^2
double delta4_n3 = delta3_n2 * delta_n; // δ^4 / n^3
this.M4 = s1.M4 + s2.M4 + n1 * n2 * (n1 * n1 - n1 * n2 + n2 * n2) * delta4_n3
+ 6.0 * (n1 * n1 * s2.M2 + n2 * n2 * s1.M2) * delta2_n2
+ 4.0 * (n1 * s2.M3 - n2 * s1.M3) * delta_n;
this.M3 = s1.M3 + s2.M3 + n1 * n2 * (n1 - n2) * delta3_n2
+ 3.0 * (n1 * s2.M2 - n2 * s1.M2) * delta_n;
this.M2 = s1.M2 + s2.M2 + n1 * n2 * delta2_n;
this.M1 = s1.M1 + n2 * delta;
super.combine(other);
}
private long n() { return getCount(); }
public double mean() { return getAverage(); }
public double variance() { return n() <= 1 ? 0 : M2 / (n() - 1); }
public double stdDev() { return sqrt(variance()); }
public double skew() { return M2 == 0 ? 0 : sqrt(n()) * M3/ pow(M2, 1.5); }
public double kurtosis() { return M2 == 0 ? 0 : n() * M4 / (M2 * M2) - 3.0; }
}
关于Java 8 重构 lambda 表达式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22881350/