node.js - 声明一个实现接口(interface)的函数

Question

我在手动创建的 .d.ts 文件中有此 TypeScript 代码:

export interface IBeforeHook {
     foo: Function,
     bar: Function
}


export type BeforeHookCallbackMode = (h: IBeforeHook) => void;
export type BeforeHookRegularMode = (h?: IBeforeHook) => Promise<any>;
export type BeforeHookObservableMode = (h?: IBeforeHook) => Observable<any>;
export type BeforeHookSubscriberMode = (h?: IBeforeHook) => Subscriber<any>;
export type BeforeHookEEMode = (h?: IBeforeHook) => EventEmitter;

type TBeforeHookTemp =
  BeforeHookCallbackMode |
  BeforeHookRegularMode |
  BeforeHookObservableMode |
  BeforeHookSubscriberMode |
  BeforeHookEEMode

我希望所有 TBeforeHook 类型都扩展/实现 IBeforeHook 接口(interface)...我该怎么做？

我想做这样的事情:

export type TBeforeHook extends TBeforeHookTemp implements IBeforeHook {

}

但这不起作用。

Answer 1

您可以定义intersection type :

export type TBeforeHook = TBeforeHookTemp & IBeforeHook;