typescript 说:
The property '
$1
' does not exist on value of type '{ (pattern: string, flags?: string): RegExp; new(pattern: string, flags?: string): RegExp; }
'
通过查看 TypeScript 0.8.2 附带的 lib.d.ts
中的定义可以解释该类型:
interface RegExp {
/**
* Executes a search on a string using a regular expression pattern, and returns an array containing the results of that search.
* @param string The String object or string literal on which to perform the search.
*/
exec(string: string): RegExpExecArray;
/**
* Returns a Boolean value that indicates whether or not a pattern exists in a searched string.
* @param string String on which to perform the search.
*/
test(string: string): bool;
/** Returns a copy of the text of the regular expression pattern. Read-only. The rgExp argument is a Regular expression object. It can be a variable name or a literal. */
source: string;
/** Returns a Boolean value indicating the state of the global flag (g) used with a regular expression. Default is false. Read-only. */
global: bool;
/** Returns a Boolean value indicating the state of the ignoreCase flag (i) used with a regular expression. Default is false. Read-only. */
ignoreCase: bool;
/** Returns a Boolean value indicating the state of the multiline flag (m) used with a regular expression. Default is false. Read-only. */
multiline: bool;
lastIndex: number;
}
declare var RegExp: {
new (pattern: string, flags?: string): RegExp;
(pattern: string, flags?: string): RegExp;
}
我的问题是如何更改/更新它以允许我引用 RegExp.$1
、RegExp.$2
等?最好是我可以单独声明的东西,因为我不打算直接编辑 lib.d.ts
(它很可能会在更新时被替换)
我试过了没用:
declare var RegExp: {
new (pattern: string, flags?: string): RegExp;
(pattern: string, flags?: string): RegExp;
$1: any;
$2: any;
$3: any;
$4: any;
$5: any;
$6: any;
$7: any;
$8: any;
$9: any;
}
我想他们实际上应该用 string
类型声明。但无论如何它都不会消除错误。
除此之外,我还很好奇这到底是什么意思(为什么声明有和没有 new
?):
new (pattern: string, flags?: string): RegExp;
(pattern: string, flags?: string): RegExp;
最佳答案
您的声明 var
已关闭。接口(interface)是开放的,所以你可以写:
interface RegExp {
$1: string;
$2: string;
// etc
}
关于第二个,这是因为 new RegExp('[A-Z]')
和 RegExp('[A-Z]')
都可以创建一个 RegExp(在类型术语,它既是可调用函数又是构造函数)。
关于javascript - typescript 和正则表达式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14650014/