我正在分享 solution 来发送 image 、audio 或 video 文件，参数使用HttpURLConnection。参数可以是(纯字符串或 JSON)。
(Android 客户端到 PHP 后端)
场景: 必须上传媒体文件(音频、视频和带参数的图像)。
媒体文件将存储在服务器文件夹中，并将参数存储到数据库中。
我遇到了一个问题，图片上传成功，而参数丢失。
找到可能的解决方案
选择 HttpURLConnection 而不是 Httpclient 作为 recommend here
您可能想知道，哪个客户端最好？
Apache HTTP 客户端在 Eclair 和 Froyo 上的错误更少。这是这些版本的最佳选择。
对于 Gingerbread 和更好的，HttpURLConnection 是最佳选择。其简单的 API 和小尺寸使其非常适合 Android。透明压缩和响应缓存可减少网络使用、提高速度并节省电池。新应用程序应该使用 HttpURLConnection；这是我们将在未来花费精力的地方。
安卓代码:
public int uploadFile(final String sourceFileUri) {
String fileName = sourceFileUri;
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File(sourceFileUri);
if (!sourceFile.isFile()) {
dialog.dismiss();
Log.e("uploadFile", "Source File not exist :" + filepath);
runOnUiThread(new Runnable() {
public void run() {
messageText.setText("Source File not exist :" + filepath);
}
});
return 0;
} else {
try {
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
// conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type","multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
//Adding Parameter name
String name="amir";
dos.writeBytes("Content-Disposition: form-data; name=\"name\"" + lineEnd);
//dos.writeBytes("Content-Type: text/plain; charset=UTF-8" + lineEnd);
//dos.writeBytes("Content-Length: " + name.length() + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(name); // mobile_no is String variable
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
//Adding Parameter phone
String phone="9956565656";
dos.writeBytes("Content-Disposition: form-data; name=\"phone\"" + lineEnd);
//dos.writeBytes("Content-Type: text/plain; charset=UTF-8" + lineEnd);
//dos.writeBytes("Content-Length: " + name.length() + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(phone); // mobile_no is String variable
dos.writeBytes(lineEnd);
//Json_Encoder encode=new Json_Encoder();
//call to encode method and assigning response data to variable 'data'
//String data=encode.encod_to_json();
//response of encoded data
//System.out.println(data);
//Adding Parameter filepath
dos.writeBytes(twoHyphens + boundary + lineEnd);
String filepath="http://192.168.1.110/echo/uploads"+fileName;
dos.writeBytes("Content-Disposition: form-data; name=\"filepath\"" + lineEnd);
//dos.writeBytes("Content-Type: text/plain; charset=UTF-8" + lineEnd);
//dos.writeBytes("Content-Length: " + name.length() + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(filepath); // mobile_no is String variable
dos.writeBytes(lineEnd);
//Adding Parameter media file(audio,video and image)
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "+ serverResponseMessage + ": " + serverResponseCode);
if (serverResponseCode == 200) {
runOnUiThread(new Runnable() {
public void run() {
msg = "File Upload Completed.\n\n See uploaded file here : \n\n"
+ "c:/wamp/www/echo/uploads";
messageText.setText(msg);
Toast.makeText(MainActivity.this,
"File Upload Complete.", Toast.LENGTH_SHORT)
.show();
}
});
}
// close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
dialog.dismiss();
ex.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
messageText
.setText("MalformedURLException Exception : check script url.");
Toast.makeText(MainActivity.this,
"MalformedURLException", Toast.LENGTH_SHORT)
.show();
}
});
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (final Exception e) {
dialog.dismiss();
e.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
messageText.setText("Got Exception : "+e.toString());
Toast.makeText(MainActivity.this,
"Got Exception : see logcat ",
Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server Exception",
"Exception : " + e.getMessage(), e);
}
dialog.dismiss();
return serverResponseCode;
}
}
php代码:
$file_path = "uploads/";
//receive parameters
$name=$_POST['name'];
$phone=$_POST['phone'];
$filepath=$_POST['filepath'];
//receive media files(image , audio and video)
$file_path = $file_path . basename( $_FILES['uploaded_file']['name']);
if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $file_path))
{
echo "Success";
}
希望这会有所帮助。
有什么问题可以问我。
最佳答案
您可以使用 Retrofit用于 API 调用。对 Android 的最低支持是 2.3。请查看详细信息。
关于android - HttpURLConnection 发送带参数的图像、音频和视频文件可能(String 或 Json String)Android，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/26686806/