iphone - 搜索只匹配开头的单词

Question

在 Apple 的一个代码示例中，他们给出了一个搜索示例:

for (Person *person in personsOfInterest)
{
    NSComparisonResult nameResult = [person.name compare:searchText
            options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch)
            range:NSMakeRange(0, [searchText length])];

    if (nameResult == NSOrderedSame)
    {
        [self.filteredListContent addObject:person];
    }
}

不幸的是，此搜索只会匹配开头的文本。如果您搜索“John”，它将匹配“John Smith”和“Johnny Rotten”，但不会匹配“Peach John”或“The John”。

有什么方法可以更改它以便在名称中的任何位置找到搜索文本？谢谢。

Answer 1

尝试使用 rangeOfString:options: 代替:

for (Person *person in personsOfInterest) {
    NSRange r = [person.name rangeOfString:searchText options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch)];

    if (r.location != NSNotFound)
    {
            [self.filteredListContent addObject:person];
    }
}

另一种实现此目的的方法是使用 NSPredicate:

NSPredicate *namePredicate = [NSPredicate predicateWithFormat:@"name CONTAINS[cd] %@", searchText];
//the c and d options are for case and diacritic insensitivity
//now you have to do some dancing, because it looks like self.filteredListContent is an NSMutableArray:
self.filteredListContent = [[[personsOfInterest filteredArrayUsingPredicate:namePredicate] mutableCopy] autorelease];


//OR YOU CAN DO THIS:
[self.filteredListContent addObjectsFromArray:[personsOfInterest filteredArrayUsingPredicate:namePredicate]];