这里我有一个编码字符串的方法(它是不完整的)，你会发现我的问题是一个错误:“指向非函数类型的 block 指针无效”
+ (NSString *)encodeString: (NSString *)string {
__block int indexShift;
__block NSString *dictionary = @"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
__block NSString *encodeDictionary = @"mahgbcjdfukripylswxovzetqnFMAJWGCQYXLOETPBKSVNIZUHDR";
__block NSString *encodeString = @"";
void (^encode) = ^{ // Error here, "Block pointer to non-function type is invalid"
for (int x = 0; x < string.length; x++) {
int index = [dictionary indexOf:[string characterAtIndex:x]];
indexShift += index;
encodeString = [encodeString stringByAppendingFormat:@"%c", [encodeDictionary characterAtIndex:index+indexShift]];
}
};
return encodeString;
}
请告诉我为什么会这样，或者我需要更改什么来修复它。
最佳答案
声明内联 block 的语法不正确。一般形式如下:
ReturnType(^block_name)(parmeter, types, here) = ^(parameter, types, here) {
};
所以你要找的是:
void(^encode)() = ^() {
};
关于objective-c - "Block pointer to non-function type is invalid"，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/11890631/