iphone - 通过 NSTimer UserInfo 传递数据

Question

我正在尝试通过 userInfo 传递数据以进行 NSTimer 调用。做这个的最好方式是什么？我正在尝试使用 NSDictionary，当我有 Objective-C 对象时这很简单，但是其他数据呢？我想做这样的事情，但它不能正常工作:

- (void)play:(SystemSoundID)sound target:(id)target callbackSelector:(SEL)selector
{
    NSLog(@"pause ipod");
    [iPodController pause];
    theSound = sound;

    NSMutableDictionary *cb = [[NSMutableDictionary alloc] init];
    [cb setObject:(id)&sound forKey:@"sound"];
    [cb setObject:target forKey:@"target"];
    [cb setObject:(id)&selector forKey:@"selector"];

    [NSTimer scheduledTimerWithTimeInterval:0
                                     target:self
                                   selector:@selector(notifyPause1:)
                                   userInfo:(id)cb
                                    repeats:NO];
}

Answer 1

您必须将信息正确地包装到字典中:

- (void) play:(SystemSoundID)sound target:(id)target callbackSelector:(SEL)selector
{
    NSLog(@"pause ipod");
    [iPodController pause];
    theSound = sound;

    NSMutableDictionary *cb = [[NSMutableDictionary alloc] init];
    [cb setObject:[NSNumber numberWithInt:sound] forKey:@"sound"];
    [cb setObject:target forKey:@"target"];
    [cb setObject:NSStringFromSelector(selector) forKey:@"selector"];

    [NSTimer scheduledTimerWithTimeInterval:0
                                     target:self
                                   selector:@selector(notifyPause1:)
                                   userInfo:cb 
                                     repeats:NO];
    [cb release];

}

在 notifyPause1: 中，您检索所有内容:

- (void)notifyPause1:(NSTimer *)timer {
    NSDictionary *dict = [timer userInfo];

    SystemSoundID sound = [[dict objectForKey:@"sound"] intValue];
    id target = [dict objectForKey:@"target"];
    SEL selector = NSSelectorFromString([dict objectForKey:@"selector"]);

    // Do whatever...
}

由于定时器是一个重复定时器，你不再需要字典了，所以你可以释放它。