python - 如何在 ctypes python 中将 char 指针作为参数传递

Question

请帮助我将下面的 c++ 代码行转换为 ctypes python:

Ret = openFcn(&Handle, "C:\\Config.xml");

下面是每个的声明:

typedef uint16_t (* OpenDLLFcnP)(void **, const char *);
OpenDLLFcnP openFcn = NULL;
openFcn = (OpenDLLFcnP) myLibrary.resolve("Open");
void *Handle = NULL;

Answer 1

myLibrary.resolve 未定义，但您需要(未经测试)的一般代码是:

import ctypes
dll = ctypes.CDLL('your.dll')
Open = dll.Open
Open.argtypes = [ctypes.POINTER(ctypes.c_void_p),ctypes.c_char_p]
Open.restype = ctypes.c_uint16
Handle = ctypes.c_void_p()
result = Open(ctypes.byref(Handle),'c:\\Config.xml')

假设您有一个名为 your.dll 的 DLL，其中包含您要调用的函数 Open。