要获取视频的时长和分辨率,我有这个函数:
def getvideosize(url, verbose=False):
try:
if url.startswith('http:') or url.startswith('https:'):
ffprobe_command = ['ffprobe', '-icy', '0', '-loglevel', 'repeat+warning' if verbose else 'repeat+error', '-print_format', 'json', '-select_streams', 'v', '-show_streams', '-timeout', '60000000', '-user-agent', BILIGRAB_UA, url]
else:
ffprobe_command = ['ffprobe', '-loglevel', 'repeat+warning' if verbose else 'repeat+error', '-print_format', 'json', '-select_streams', 'v', '-show_streams', url]
logcommand(ffprobe_command)
ffprobe_process = subprocess.Popen(ffprobe_command, stdout=subprocess.PIPE)
try:
ffprobe_output = json.loads(ffprobe_process.communicate()[0].decode('utf-8', 'replace'))
except KeyboardInterrupt:
logging.warning('Cancelling getting video size, press Ctrl-C again to terminate.')
ffprobe_process.terminate()
return 0, 0
width, height, widthxheight, duration = 0, 0, 0, 0
for stream in dict.get(ffprobe_output, 'streams') or []:
if dict.get(stream, 'duration') > duration:
duration = dict.get(stream, 'duration')
if dict.get(stream, 'width')*dict.get(stream, 'height') > widthxheight:
width, height = dict.get(stream, 'width'), dict.get(stream, 'height')
if duration == 0:
duration = 1800
return [[int(width), int(height)], int(float(duration))+1]
except Exception as e:
logorraise(e)
return [[0, 0], 0]
但有些在线视频没有duration
标签。我们可以做些什么来获得它的持续时间吗?
最佳答案
如果您有指向视频本身的直接链接,例如 http://www.dl.com/xxx.mp4 ,您可以直接使用 ffprobe
获取此视频的持续时间,方法是:
ffprobe -i some_video_direct_link -show_entries format=duration -v quiet -of csv="p=0"
关于python - 如何在不下载完整视频的情况下获取在线视频的时长?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26974921/