python - 是否可以在没有双重拆分的情况下从未解析的字符串列表构造字典理解？

Question

<分区>

Answer 1

直接使用元组如 dict:

代码:

patternMap = dict(x.split('=') for x in foo)

测试代码:

foo = ['super capital=BLUE', 'super foo=RED']
patternMap = {x.split("=")[0]: x.split("=")[1] for x in foo}
print(patternMap)

patternMap = dict(x.split('=') for x in foo)
print(patternMap)

# or if you really need a longer way
patternMap = {y[0]: y[1] for y in (x.split('=') for x in foo)}
print(patternMap)

结果:

{'super capital': 'BLUE', 'super foo': 'RED'}
{'super capital': 'BLUE', 'super foo': 'RED'}
{'super capital': 'BLUE', 'super foo': 'RED'}