Python:是否可以有一个类方法作用于类的一部分?

标签 python list slice

我正在用 Python 制作一个容器类,它要么继承自 list,要么只实现所有标准列表方法(我真的不在乎是哪个)。

我将如何创建一个仅作用于从切片返回的项目的方法?我已经能够创建一个将作用于整个容器的方法(见下文),但我似乎无法弄清楚如何只作用于切片。

我正在使用 python 2.7.6 并在我的所有代码中使用 from __future__ import print_function, division

示例代码:

from __future__ import print_function, division
import itertools

class MyContainerClass(list):
    """ For now, I'm inheriting from list. Is this my problem? """
    def __init__(self, data_array):
        list.__init__(self, data_array)

    def __getitem__(self, *args):

        arg = args[0]

        # specific indices   MyContainerClass[0, 3, 5] => indexes 0, 3, and 5
        if isinstance(arg, (list, tuple)) and not isinstance(arg[0], bool):
            return [list.__getitem__(self, _i) for _i in arg]

        # standard slice notation
        elif isinstance(arg, slice):
            return list.__getitem__(self, arg)

        # Using an array mask   MyContainerClass[[True, False, False,...,True]] => index 0 and -1]
        elif isinstance(arg[0], bool):  # or isinstance(arg, np.ndarray):
            return list(itertools.compress(self, arg))

        else:
            # I'll eventually replace this with and exception raise.
            return 'error'

    def my_method(self):
        """
        Will act on entire list, but I want it to act on only what's
        returned by the slice (which may be the entire list in some cases).
        """
        return "a, ".join([str(_i) for _i in self])

这是我想要的用法示例:

>>> data = MyContainerClass([1, 2, 3, 4, 5, 6, 7])
>>> data[5:]
[6, 7]
>>> data.my_method()           # This works as expected
"1a, 2a, 3a, 4a, 5a, 6a, 7"
>>> data[0:3].my_method()      # Doesn't work
"1a, 2a, 3"                    # but should return this


看起来一切正常。谢谢一群人!这是我想出的:

from __future__ import print_function, division
import itertools

class MyContainerClass(list):
    """
    """
    def __init__(self, array):
        if isinstance(array, int):
            list.__init__(self, [array])
        else:
            list.__init__(self, array)

    def __getitem__(self, arg):
        # Standard Slice notation
        if isinstance(arg, slice):
            retval = super(MyContainerClass, self).__getitem__(arg)

        # specific indices
        elif isinstance(arg, (list, tuple)) and not isinstance(arg[0], bool):
            retval = [list.__getitem__(self, _i) for _i in arg]

        # a single specific index
        elif isinstance(arg, int):
            retval = list.__getitem__(self, arg)

        # an array mask of T/F values
        elif isinstance(arg[0], bool):      # or isinstance(arg, np.ndarray):
            retval = list(itertools.compress(self, arg))

        # raise an error on unknown
        else:
            raise SyntaxError("Unknown notation for list slice or index")

        retval = type(self)(retval)
        return retval

    def __getslice__(self, i, j):
        # Python 2 built-in types only
        return self.__getitem__(slice(i, j))

    def my_method(self):
        return "a, ".join([str(_i) for _i in self])

并且表现得像:

>>> data = MyContainerClass([1, 2, 3, 4, 5, 6, 7])
>>> mask = [True, True, False, True, False, False, False]
>>> print(data)
[1, 2, 3, 4, 5, 6, 7]
>>> print(type(data[5:]))
<class '__main__.MyContainerClass'>
>>> print(data.my_method())
1a, 2a, 3a, 4a, 5a, 6a, 7
>>> print(data[0:5].my_method())
1a, 2a, 3a, 4a, 5
>>> print(data[1, 5, 2].my_method())
2a, 6a, 3
>>> print(data[mask].my_method())
1a, 2a, 4
>>> print(data[2].my_method())
3

最佳答案

您必须确保您的 __getitem__ 再次返回您的类型:

class MyContainerClass(list):
    """ For now, I'm inheriting from list. Is this my problem? """
    def __init__(self, data_array):
        list.__init__(self, data_array)

    def my_method(self):
        """
        Will act on entire list, but I want it to act on only what's
        returned by the slice (which may be the entire list in some cases).
        """
        return "a, ".join([str(_i) for _i in self])

    def __getitem__(self, index):
        retval = super(MyContainerClass, self).__getitem__(index)
        if isinstance(index, slice):
            retval = type(self)(retval)
        return retval

    def __getslice__(self, i, j):
        # Python 2 built-in types only
        return self.__getitem__(slice(i, j))

额外的__getslice__ method仅在 Python 2 中需要,并且仅当您从已实现 __getslice__ 的类型继承时才需要。 list就是这样一种类型。

演示:

>>> data = MyContainerClass([1, 2, 3, 4, 5, 6, 7])
>>> data[:5]
[1, 2, 3, 4, 5]
>>> type(data[:5])
<class '__main__.MyContainerClass'>
>>> data.my_method()
'1a, 2a, 3a, 4a, 5a, 6a, 7'
>>> data[:3].my_method()
'1a, 2a, 3'

关于Python:是否可以有一个类方法作用于类的一部分?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25511436/

相关文章:

javascript - ImmutableJS 设置不扁平化

android - 如何在列表中创建列表?

用不均匀向量列表中的正值替换正表值

go - 在 Go 中连接两个 slice

python - Scipy稀疏矩阵切片返回IndexError

python - Beautiful Soup find_all() 返回奇数标签而不是结果

python - 迭代变量参数的元素

python:哪个文件更新了多少时间

string - slice 后释放字符串以进行垃圾回收的正确方法

Python C API sys.getsizeof()