python - 比较python中的两个字典以获得相似键的最大值

Question

我有这两个命令:

a={"test1":90,  "test2":45,  "test3":67,  "test4":74}
b={"test1":32,  "test2":45,  "test3":82,  "test4":100}

如何提取相同键的最大值以获得新的字典，如下所示:

c={"test1":90,  "test2":45,  "test3":82,  "test4":100}

Answer 1

你可以这样试试，

>>> a={"test1":90, "test2":45, "test3":67, "test4":74} 
>>> b={"test1":32, "test2":45, "test3":82, "test4":100}
>>> c = { key:max(value,b[key]) for key, value in a.iteritems() }
>>> c
{'test1': 90, 'test3': 82, 'test2': 45, 'test4': 100}