假设我有这个文件:
1
17:02,111
Problem report related to
router
2
17:05,223
Restarting the systems
3
18:02,444
Must erase hard disk
now due to compromised data
我想要这个输出:
1
17:02,111
Problem report related to router
2
17:05,223
Restarting the systems
3
18:02,444
Must erase hard disk now due to compromised data
一直在 bash 中尝试并找到了一种接近的解决方案,但我不知道如何在 Python 上执行此操作。
提前致谢
最佳答案
如果你想删除 extea 线:
为了这个目的,如果该行后面没有空新行,或者该行之前应该有一个与以下正则表达式 ^\d{2} 匹配的行,您可以为每个类似的条件检查 2 个条件:\d{2},\d{3}\s$
.
因此,为了在每次迭代中访问下一行,您可以使用 itertools.tee
从主文件对象创建一个名为 temp
的文件对象。并在其上应用 next
函数。并使用 re.match
来匹配正则表达式。
from itertools import tee
import re
with open('ex.txt') as f,open('new.txt','w') as out:
temp,f=tee(f)
next(temp)
try:
for line in f:
if next(temp) !='\n' or re.match(r'^\d{2}:\d{2},\d{3}\s$',pre):
out.write(line)
pre=line
except :
pass
结果:
1
17:02,111
Problem report related to
2
17:05,223
Restarting the systems
3
18:02,444
Must erase hard disk
如果你想将其余部分连接到第三行:
如果您想将第三行之后的其余行连接到第三行,您可以使用以下正则表达式来查找后跟 \n\n
或文件末尾 ( $
) :
r"(.*?)(?=\n\n|$)"
然后根据日期格式的行拆分块并将部分写入输出文件,但请注意您需要用空格替换第三部分中的新行:
ex.txt:
1
17:02,111
Problem report related to
router
another line
2
17:05,223
Restarting the systems
3
18:02,444
Must erase hard disk
now due to compromised data
line 5
line 6
line 7
演示:
def splitter(s):
for x in re.finditer(r"(.*?)(?=\n\n|$)", s,re.DOTALL):
g=x.group(0)
if g:
yield g
import re
with open('ex.txt') as f,open('new.txt','w') as out:
for block in splitter(f.read()):
first,second,third= re.split(r'(\d{2}:\d{2},\d{3}\n)',block)
out.write(first+second+third.replace('\n',' '))
结果:
1
17:02,111
Problem report related to router another line
2
17:05,223
Restarting the systems
3
18:02,444
Must erase hard disk now due to compromised data line 5 line 6 line 7
注意:
在这个答案中,splitter
函数返回一个生成器,当您处理大文件并拒绝在内存中存储不可用的行时,该生成器非常高效。
关于Python。在 1 行加入特定行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30934765/