我有一个要在其中存储位的对象。
class Bitset:
def __init__(self, bitstring):
self.bitlist = []
for char in bitstring:
self.bitlist.append(int(char))
def flipBit(self, index):
val = self.bitlist[index]
val = (val + 1) % 2
self.bitlist[index] = val
self.newBitstring()
def bitstring(self):
newString = ''
for val in self.bitlist:
newString = newString + str(val)
return newString
def __len__(self):
return len(self.bitlist)
def __str__(self):
return self.bitstring()
def __repr__(self):
return self.bitstring()
无论如何我可以将位转换为 float 吗?谢谢。
最佳答案
这是一个可行的解决方案。 as_float32 可以扩展为 as_float64,方法是将“I”替换为“L”,将“f”替换为“d”。查看struct documentation寻求解释。
def as_float32(self):
"""
See: http://en.wikipedia.org/wiki/IEEE_754-2008
"""
from struct import pack,unpack
s = self.bitlist
return unpack("f",pack("I", bits2int(s)))
# Where the bits2int function converts bits to an integer.
def bits2int(bits):
# You may want to change ::-1 if depending on which bit is assumed
# to be most significant.
bits = [int(x) for x in bits[::-1]]
x = 0
for i in range(len(bits)):
x += bits[i]*2**i
return x
关于python - 将二进制字符串转换为 float ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7395806/