如何修改下面自定义 QMessageBox 的代码,以便了解用户点击的是"is"还是“否”?
from PySide import QtGui, QtCore
# Create a somewhat regular QMessageBox
msgBox = QtGui.QMessageBox( QtGui.QMessageBox.Question, "My title", "My text.", QtGui.QMessageBox.Yes | QtGui.QMessageBox.No )
# Get the layout
question_layout = msgBox.layout()
# Additional widgets to add to the QMessageBox
qlabel_workspace_project = QtGui.QLabel('Some random data window:')
qtextedit_workspace_project = QtGui.QTextEdit()
qtextedit_workspace_project.setReadOnly(True)
# Add the new widgets
question_layout.addWidget(qlabel_workspace_project,question_layout.rowCount(), 0, 1, question_layout.columnCount() )
question_layout.addWidget(qtextedit_workspace_project,question_layout.rowCount(), 0, 1, question_layout.columnCount() )
# Show widget
msgBox.show()
最佳答案
您应该使用exec_
方法而不是show
,所有从QDialog
继承的小部件都具有:
http://doc.qt.io/qt-4.8/qmessagebox.html#exec
此方法会阻塞,直到关闭消息框并返回结果:
result = msgBox.exec_()
if result == QtGui.QMessageBox.Yes:
# do yes-action
else:
# do no-action
关于python - 如何从自定义的 QMessageBox 中捕获按钮点击?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25570194/