python - 将列表转换为十六进制字符串的优雅方式

Question

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Answer 1

加入单线俱乐部，通过位操作的方式似乎更合适。

val = hex(reduce(lambda total, wall: total << 1 | wall, walls, 0))

这与:

val = 0
for wall in walls:
    val <<= 1 # add one 0 bit at the "end"
    val |= wall # set this bit to 1 if wall is True, otherwise leave it at 0

val = hex(val) # get a hex string in the end
val = format(val, 'x') # or without the leading 0x if it's undesired