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如何获取下面两段文字引号之间的内容？
text_1 = r""" "Some text on \"two\" lines with a backslash escaped\\" \
+ "Another text on \"three\" lines" """
text_2 = r""" "Some text on \"two\" lines with a backslash escaped\\" + "Another text on \"three\" lines" """
对我来说问题是引号如果被转义应该被忽略，但是反斜杠有可能被转义。
我想获取以下组。
[
r'Some text on \"two\" lines with a backslash escaped\\',
r'Another text on \"three\" lines'
]
最佳答案
"(?:\\.|[^"\\])*"
匹配带引号的字符串，包括其中出现的任何转义字符。
解释:
" # Match a quote.
(?: # Either match...
\\. # an escaped character
| # or
[^"\\] # any character except quote or backslash.
)* # Repeat any number of times.
" # Match another quote.
关于python - REGEX 字符串和转义引号，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16130404/