c - C中位域的内存管理

Question

为了理解位域内存存储，我创建了下面的测试程序。

#include <stdio.h>

int main()
{
    int a;
    typedef struct {
        int b7 : 1;
        int b6 : 1;
        int b5 : 1;
        int b4 : 1;
        int b3 : 1;
        int b2 : 1;
        int b1 : 1;
        int b0 : 1;
    } byte;

    byte ab0 = {0,0,0,0,0,0,0,1};
    a = *(int*)&ab0;
    printf("ab0 is %x \n",a);

    byte ab1 = {0,0,0,0,0,0,1,0};
    a = *(int*)&ab1;
    printf("ab1 is %x \n",a);

    byte ab2 = {0,0,0,0,0,1,0,0};
    a = *(int*)&ab2;
    printf("ab2 is %x \n",a);

    byte ab3 = {0,0,0,0,1,0,0,0};
    a = *(int*)&ab3;
    printf("ab3 is %x \n",a);

    byte ab4 = {0,0,0,1,0,0,0,0};
    a = *(int*)&ab4;
    printf("ab4 is %x \n",a);

    byte ab5 = {0,0,1,0,0,0,0,0};
    a = *(int*)&ab5;
    printf("ab5 is %x \n",a);

    byte ab6 = {0,1,0,0,0,0,0,0};
    a = *(int*)&ab6;
    printf("ab6 is %x \n",a);

    byte ab7 = {1,0,0,0,0,0,0,0};
    a = *(int*)&ab7;
    printf("ab7 is %x \n",a);

    return 0;
}

编译运行

gcc -Wall test.c
./a.out 
ab0 is 80 
ab1 is 40 
ab2 is 20 
ab3 is 10 
ab4 is 8 
ab5 is 4 
ab6 is 2 
ab7 is 1 

当我在线运行代码时，输​​出相同 http://codepad.org/ntqyuixp

我无法理解它的输出。

预期输出: 根据我的理解，输出应该是

ab0 is 1 
ab1 is 2 
ab2 is 4 
ab3 is 8 
ab4 is 10 
ab5 is 20 
ab6 is 40 
ab7 is 80

• 请让我知道我缺少什么。

• 字节序有什么作用吗？

• 应如何为我的预期行为编写代码？

Answer 1

位域中位的顺序由实现定义。该实现的定义与您预期的不同——这几乎就是所有关于它的内容。

几乎所有关于位域的内容都是由实现定义的。

ISO/IEC 9899:2011 §6.7.2.1 结构和 union 说明符

¶4 The expression that specifies the width of a bit-field shall be an integer constant expression with a nonnegative value that does not exceed the width of an object of the type that would be specified were the colon and expression omitted.¹²²⁾ If the value is zero, the declaration shall have no declarator.

¶5 A bit-field shall have a type that is a qualified or unqualified version of _Bool, signed int, unsigned int, or some other implementation-defined type. It is implementation-defined whether atomic types are permitted.

…

¶9 A member of a structure or union may have any complete object type other than a variably modified type.¹²³⁾ In addition, a member may be declared to consist of a specified number of bits (including a sign bit, if any). Such a member is called a bit-field;¹²⁴⁾ its width is preceded by a colon.

¶10 A bit-field is interpreted as having a signed or unsigned integer type consisting of the specified number of bits.¹²⁵⁾ If the value 0 or 1 is stored into a nonzero-width bit-field of type _Bool, the value of the bit-field shall compare equal to the value stored; a _Bool bit-field has the semantics of a _Bool.

¶11 An implementation may allocate any addressable storage unit large enough to hold a bitfield. If enough space remains, a bit-field that immediately follows another bit-field in a structure shall be packed into adjacent bits of the same unit. If insufficient space remains, whether a bit-field that does not fit is put into the next unit or overlaps adjacent units is implementation-defined. The order of allocation of bit-fields within a unit (high-order to low-order or low-order to high-order) is implementation-defined. The alignment of the addressable storage unit is unspecified.

¶12 A bit-field declaration with no declarator, but only a colon and a width, indicates an unnamed bit-field.¹²⁶⁾ As a special case, a bit-field structure member with a width of 0 indicates that no further bit-field is to be packed into the unit in which the previous bitfield, if any, was placed.

¹²²⁾ While the number of bits in a _Bool object is at least CHAR_BIT, the width (number of sign and value bits) of a _Bool may be just 1 bit.

¹²³⁾ A structure or union cannot contain a member with a variably modified type because member names are not ordinary identifiers as defined in 6.2.3.

¹²⁴⁾ The unary & (address-of) operator cannot be applied to a bit-field object; thus, there are no pointers to or arrays of bit-field objects.

¹²⁵⁾ As specified in 6.7.2 above, if the actual type specifier used is int or a typedef-name defined as int, then it is implementation-defined whether the bit-field is signed or unsigned.

¹²⁶⁾ An unnamed bit-field structure member is useful for padding to conform to externally imposed layouts.

特别注意¶11:

The order of allocation of bit-fields within a unit (high-order to low-order or low-order to high-order) is implementation-defined.

还要注意，“实现定义”意味着实现必须定义它的作用。也就是说，您可以检查文档，并且文档必须告诉您编译器做了什么(如果编译器符合标准)。这与“未指定”以及您将遇到的其他一些术语不同——编译器编写者几乎肯定不会随意更改位域的行为。相比之下，评估函数参数的方式，例如，可能会因版本而异，或者根据编译时选择的优化选项等而变化。

§6.5.2.2 Function calls

There is a sequence point after the evaluations of the function designator and the actual arguments but before the actual call. Every evaluation in the calling function (including other function calls) that is not otherwise specifically sequenced before or after the execution of the body of the called function is indeterminately sequenced with respect to the execution of the called function.⁹⁴⁾

⁹⁴⁾ In other words, function executions do not ‘‘interleave’’ with each other.

6.7.2 Type specifiers

5 Each of the comma-separated multisets designates the same type, except that for bit-fields, it is implementation-defined whether the specifier int designates the same type as signed int or the same type as unsigned int.