python - 如何使 "ValueError"异常替换列表中的项目

Question

我正在尝试编写一段代码，它将遍历数字列表(在垂直条上拆分)，如果用户输入非数字，将抛出异常并将所述对象替换为 0。它旨在按降序(从大到小)显示列表，中间有竖线。 这是我目前的代码，但我无法让它工作。

    numbers = input("Please enter several integer numbers separated by 
    vertical bars. ").split('|')
    for item in numbers:
        try:
            numbers = [int(item) for item in numbers]
        except ValueError:
            item = item.replace(item,'0')
    numbers = sorted(numbers, reverse = True)
    print(' | '.join(str(num) for num in numbers))

Answer 1

numbers = input("Please enter several integer numbers separated by vertical bars. ")
numbers = numbers.split('|')
temp = []
for item in numbers:
    try:
        temp.append(int(item))
    except ValueError:
        temp.append(0)
numbers = temp

请注意，我们在迭代时不会更改 numbers。完成相同任务的另一种方法是类似

def eval_number(s):
    try:
        return int(s)
    except ValueError:
        return 0

numbers = input("Please enter several integer numbers separated by vertical bars. ")
numbers = numbers.split('|')
numbers = list(map(eval_number, numbers))