Pygame 鼠标事件中的 Python 时间计数器

Question

我想计算 Pygame 中用户鼠标事件的时间，如果用户在大约 15 秒内没有移动鼠标，那么我想在屏幕上显示文本。我为此尝试了 time 模块，但它不起作用。

import pygame,time

pygame.init()

#codes
...
...

font = pygame.font.SysFont(None,25)
text = font.render("Move your mouse!", True, red)

FPS = 30

while True:
    #codes
    ... 
    ...
    start = time.time()
    cur = pygame.mouse.get_pos() #catching mouse event 
    end = time.time()
    diff = end-start
    if 15 < diff:
        gameDisplay.blit(text,(10,500))

    pygame.display.update()

    clock.tick(FPS)

pygame.quit()
quit()

输出不是我想要的，如果用户不移动他的鼠标，我不知道如何计算它。

If I want to write a text when user's mouse in a special area, it's working like;

if 100 < cur[0] < 200 and 100 < cur[1] < 200:
        gameDisplay.blit(text,(10,500))

但是我该如何计算呢？我什至找不到如何告诉 Python，用户的鼠标是否在同一坐标上。然后我可以说，如果鼠标坐标发生变化，则启动计时器，如果它大于 15，则打印文本。

Edit: You can assume it in normal Python without Pygame module, assume you have a function that catching the mouse events, then how to tell Python if coordinates of mouse doesn't change, start the timer, if the time is bigger than 15 seconds,print a text, then refresh the timer.

Answer 1

如果 pygame 窗口内没有鼠标移动 3 秒，则在屏幕上显示文本:

#!/usr/bin/python
import sys
import pygame

WHITE, RED = (255,255,255), (255,0,0)
pygame.init()
screen = pygame.display.set_mode((300,200))
pygame.display.set_caption('Warn on no movement')

font = pygame.font.SysFont(None, 25)
text = font.render("Move your mouse!", True, RED, WHITE)

clock = pygame.time.Clock()
timer = pygame.time.get_ticks
timeout = 3000 # milliseconds
deadline = timer() + timeout
while True:
    now = timer()
    if pygame.mouse.get_rel() != (0, 0): # mouse moved within the pygame screen
        deadline = now + timeout # reset the deadline

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            sys.exit()

    screen.fill(WHITE)
    if now > deadline: # no movement for too long
        screen.blit(text, (10, 50))

    pygame.display.flip()
    clock.tick(60) # set fps