Python新手，等于字符串？

Question

我想弄清楚为什么我无法将 IP 的输出与设置的 IP 进行匹配并因此呈现结果。

import urllib
import re

ip = '212.125.222.196'

url = "http://checkip.dyndns.org"

print url

request = urllib.urlopen(url).read()

theIP = re.findall(r"\d{1,3}\.\d{1,3}\.\d{1,3}.\d{1,3}", request)

print "your IP Address is: ",  theIP

if theIP == '211.125.122.192':
    print "You are OK"
else:
    print "BAAD"

结果总是“糟糕”

Answer 1

re.findall 返回匹配列表，而不是字符串。所以你现在有两个选择，要么遍历列表并使用 any:

theIP = re.findall(r"\d{1,3}\.\d{1,3}\.\d{1,3}.\d{1,3}", request)
if any(ip == '211.125.122.192' for ip in theIP):
    print "You are OK"
else:
    print "BAAD"  

#or simply:

if '211.125.122.192' in theIp:
    print "You are OK"
else:
    print "BAAD"  

或使用re.search:

theIP = re.search(r"\d{1,3}\.\d{1,3}\.\d{1,3}.\d{1,3}", request)
if theIP and (theIP.group() == '211.125.122.192'):
    print "You are OK"
else:
    print "BAAD"