python - 如何获取没有目录名的文件名

Question

如何在结果中只列出目录中没有目录信息的文件名？我试过了

for file in glob.glob(dir+filetype):
    print file

给我结果 /path_name/1.log,/path_name/2.log,.... 但我只需要文件名:1.log、2.log 等。我不需要结果中的目录信息。有没有简单的方法来摆脱路径信息？我不想对结果进行一些修改。谢谢!

Answer 1

os.path.basename :

Return the base name of pathname path. This is the second element of the pair returned by passing path to the function split(). Note that the result of this function is different from the Unix basename program; where basename for '/foo/bar/' returns 'bar', the basename() function returns an empty string ('').

所以:

>>> os.path.basename('/path_name/1.log,/path_name/2.log')
'2.log'