我目前正在使用来自 Here 的目录 walker
import os
class DirectoryWalker:
# a forward iterator that traverses a directory tree
def __init__(self, directory):
self.stack = [directory]
self.files = []
self.index = 0
def __getitem__(self, index):
while 1:
try:
file = self.files[self.index]
self.index = self.index + 1
except IndexError:
# pop next directory from stack
self.directory = self.stack.pop()
self.files = os.listdir(self.directory)
self.index = 0
else:
# got a filename
fullname = os.path.join(self.directory, file)
if os.path.isdir(fullname) and not os.path.islink(fullname):
self.stack.append(fullname)
return fullname
for file in DirectoryWalker(os.path.abspath('.')):
print file
这个小改动允许您在文件中拥有完整路径。
任何人都可以帮助我如何使用它来查找文件名吗?我需要完整路径和文件名。
最佳答案
你为什么要自己做这么无聊的事情?
for path, directories, files in os.walk('.'):
print 'ls %r' % path
for directory in directories:
print ' d%r' % directory
for filename in files:
print ' -%r' % filename
输出:
'.'
d'finction'
d'.hg'
-'setup.py'
-'.hgignore'
'./finction'
-'finction'
-'cdg.pyc'
-'util.pyc'
-'cdg.py'
-'util.py'
-'__init__.pyc'
-'__init__.py'
'./.hg'
d'store'
-'hgrc'
-'requires'
-'00changelog.i'
-'undo.branch'
-'dirstate'
-'undo.dirstate'
-'branch'
'./.hg/store'
d'data'
-'undo'
-'00changelog.i'
-'00manifest.i'
'./.hg/store/data'
d'finction'
-'.hgignore.i'
-'setup.py.i'
'./.hg/store/data/finction'
-'util.py.i'
-'cdg.py.i'
-'finction.i'
-'____init____.py.i'
但如果你坚持,os.path 中有路径相关的工具, os.basename 就是你正在看的。
>>> import os.path
>>> os.path.basename('/hello/world.h')
'world.h'
关于python - 用于 Python 的 Directory Walker,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/775231/