PostgreSQL 和 SQL 定义了一个 Serializable transaction isolation level .如果您将事务隔离到此级别，则冲突的并发事务将中止并需要重试。
我熟悉 Plone/Zope 世界中事务重试的概念，如果出现事务冲突，整个 HTTP 请求可以重放。如何使用 SQLAlchemy(并可能使用 zope.sqlalchemy)实现类似的功能？我试着阅读 zope.sqlalchemy 和 Zope transaction manager 的文档，但这对我来说并不明显。
特别是我想要这样的东西:
# Try to do the stuff, if it fails because of transaction conflict do again until retry count is exceeded
with transaction.manager(retries=3):
do_stuff()
# If we couldn't get the transaction through even after 3 attempts, fail with a horrible exception
最佳答案
因此，在摸索了大约两周但没有找到现成的解决方案后，我想出了自己的解决方案。
这是一个 ConflictResolver 类，它提供了 managed_transaction 函数装饰器。您可以使用装饰器将函数标记为可重试。 IE。如果运行该函数时出现数据库冲突错误，则再次运行该函数，现在更有希望导致冲突错误的数据库事务已经完成。
仅限 Python 3.4+。
"""Serialized SQL transaction conflict resolution as a function decorator."""
import warnings
import logging
from collections import Counter
from sqlalchemy.orm.exc import ConcurrentModificationError
from sqlalchemy.exc import OperationalError
UNSUPPORTED_DATABASE = "Seems like we might know how to support serializable transactions for this database. We don't know or it is untested. Thus, the reliability of the service may suffer. See transaction documentation for the details."
#: Tuples of (Exception class, test function). Behavior copied from _retryable_errors definitions copied from zope.sqlalchemy
DATABASE_COFLICT_ERRORS = []
try:
import psycopg2.extensions
except ImportError:
pass
else:
DATABASE_COFLICT_ERRORS.append((psycopg2.extensions.TransactionRollbackError, None))
# ORA-08177: can't serialize access for this transaction
try:
import cx_Oracle
except ImportError:
pass
else:
DATABASE_COFLICT_ERRORS.append((cx_Oracle.DatabaseError, lambda e: e.args[0].code == 8177))
if not DATABASE_COFLICT_ERRORS:
# TODO: Do this when cryptoassets app engine is configured
warnings.warn(UNSUPPORTED_DATABASE, UserWarning, stacklevel=2)
#: XXX: We need to confirm is this the right way for MySQL, SQLIte?
DATABASE_COFLICT_ERRORS.append((ConcurrentModificationError, None))
logger = logging.getLogger(__name__)
class CannotResolveDatabaseConflict(Exception):
"""The managed_transaction decorator has given up trying to resolve the conflict.
We have exceeded the threshold for database conflicts. Probably long-running transactions or overload are blocking our rows in the database, so that this transaction would never succeed in error free manner. Thus, we need to tell our service user that unfortunately this time you cannot do your thing.
"""
class ConflictResolver:
def __init__(self, session_factory, retries):
"""
:param session_factory: `callback()` which will give us a new SQLAlchemy session object for each transaction and retry
:param retries: The number of attempst we try to re-run the transaction in the case of transaction conflict.
"""
self.retries = retries
self.session_factory = session_factory
# Simple beancounting diagnostics how well we are doing
self.stats = Counter(success=0, retries=0, errors=0, unresolved=0)
@classmethod
def is_retryable_exception(self, e):
"""Does the exception look like a database conflict error?
Check for database driver specific cases.
:param e: Python Exception instance
"""
if not isinstance(e, OperationalError):
# Not an SQLAlchemy exception
return False
# The exception SQLAlchemy wrapped
orig = e.orig
for err, func in DATABASE_COFLICT_ERRORS:
# EXception type matches, now compare its values
if isinstance(orig, err):
if func:
return func(e)
else:
return True
return False
def managed_transaction(self, func):
"""SQL Seralized transaction isolation-level conflict resolution.
When SQL transaction isolation level is its highest level (Serializable), the SQL database itself cannot alone resolve conflicting concurrenct transactions. Thus, the SQL driver raises an exception to signal this condition.
``managed_transaction`` decorator will retry to run everyhing inside the function
Usage::
# Create new session for SQLAlchemy engine
def create_session():
Session = sessionmaker()
Session.configure(bind=engine)
return Session()
conflict_resolver = ConflictResolver(create_session, retries=3)
# Create a decorated function which can try to re-run itself in the case of conflict
@conflict_resolver.managed_transaction
def myfunc(session):
# Both threads modify the same wallet simultaneously
w = session.query(BitcoinWallet).get(1)
w.balance += 1
# Execute the conflict sensitive code inside a managed transaction
myfunc()
The rules:
- You must not swallow all exceptions within ``managed_transactions``. Example how to handle exceptions::
# Create a decorated function which can try to re-run itself in the case of conflict
@conflict_resolver.managed_transaction
def myfunc(session):
try:
my_code()
except Exception as e:
if ConflictResolver.is_retryable_exception(e):
# This must be passed to the function decorator, so it can attempt retry
raise
# Otherwise the exception is all yours
- Use read-only database sessions if you know you do not need to modify the database and you need weaker transaction guarantees e.g. for displaying the total balance.
- Never do external actions, like sending emails, inside ``managed_transaction``. If the database transaction is replayed, the code is run twice and you end up sending the same email twice.
- Managed transaction section should be as small and fast as possible
- Avoid long-running transactions by splitting up big transaction to smaller worker batches
This implementation heavily draws inspiration from the following sources
- http://stackoverflow.com/q/27351433/315168
- https://gist.github.com/khayrov/6291557
"""
def decorated_func():
# Read attemps from app configuration
attempts = self.retries
while attempts >= 0:
session = self.session_factory()
try:
result = func(session)
session.commit()
self.stats["success"] += 1
return result
except Exception as e:
if self.is_retryable_exception(e):
session.close()
self.stats["retries"] += 1
attempts -= 1
if attempts < 0:
self.stats["unresolved"] += 1
raise CannotResolveDatabaseConflict("Could not replay the transaction {} even after {} attempts".format(func, self.retries)) from e
continue
else:
session.rollback()
self.stats["errors"] += 1
# All other exceptions should fall through
raise
return decorated_func
关于python - SQLAlchemy，以惯用的 Python 方式隔离和重试可序列化的事务，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/27351433/