c++ - 从字符串序列中提取最后 2 个单词，以空格分隔

Question

我有任何序列(或句子)，我想提取最后 2 个字符串。

例如，

• sdfsdfds sdfs dfsd fgsd 3 dsfds 应该产生:3 dsfds
• sdfsd (dfgdg)gfdg fg 6 gg 应该产生:6 gg

Answer 1

您可以使用 std::string::find_last_of查找空格的函数。

int main()
{
    std::string test = "sdfsdfds sdfs dfsd fgsd 3 dsfds";

    size_t found1 = test.find_last_of( " " );
    if ( found1 != string::npos ) {
        size_t found2 = test.find_last_of( " ", found1-1 );
        if ( found2 != string::npos ) 
            std::cout << test.substr(found2+1, found1-found2-1) << std::endl;
        std::cout << test.substr(found1+1) << std::endl;
    }

    return 0;
}