我发现这里的一些帖子讨论了运算符重载和不能在 c++ 中重载的运算符，例如 . :: .* sizeof 等。但是我找不到关于为什么要避免 .* 的确切细节或原因？你们中很少有人会认为它是重复的，但如果我能在这些链接上获得关于我想要的内容的详细信息，我会非常高兴:)
最佳答案
来自Horse's mouth :
Operator
.(dot) could in principle be overloaded using the same technique as used for ->. However, doing so can lead to questions about whether an operation is meant for the object overloading.or an object referred to by.For example:
class Y {
public:
void f();
// ...
};
class X { // assume that you can overload .
Y* p;
Y& operator.() { return *p; }
void f();
// ...
};
void g(X& x)
{
x.f(); // X::f or Y::f or error?
}
This problem can be solved in several ways. At the time of standardization, it was not obvious which way would be best.
AFAIU 同样的推理适用于 .*
关于c++ - 为什么 .* 运算符不能在 C++ 中重载？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/12077322/