c++ - Regex\w 在 C++11 中转义

Question

此代码没有返回任何内容，我是否以错误的方式转义了 w 字符？

http://liveworkspace.org/code/3bRWOJ $38

#include <iostream>
#include <regex>
using namespace std;



int main()
{
    const char *reg_esp = "\w";  // List of separator characters.

// this can be done using raw string literals:
// const char *reg_esp = R"([ ,.\t\n;:])";

std::regex rgx(reg_esp); // 'regex' is an instance of the template class
                         // 'basic_regex' with argument of type 'char'.
std::cmatch match; // 'cmatch' is an instance of the template class
                   // 'match_results' with argument of type 'const char *'.
const char *target = "Unseen University - Ankh-Morpork";

// Identifies all words of 'target' separated by characters of 'reg_esp'.
if (std::regex_search(target, match, rgx)) {
    // If words separated by specified characters are present.

    const size_t n = match.size();
    for (size_t a = 0; a < n; a++) {
        std::string str (match[a].first, match[a].second);
        std::cout << str << "\n";
    }
}

    return 0;
}

Answer 1

正则表达式应包含\w，由两个字符\和w组成，因此您的C++源代码应包含"\\w" 因为您需要转义反斜杠。