c++ - 搜索数组的上限

Question

我正在尝试获取数组 size 中最近上限(除非找到等效值)的索引使用变量 sum 中的值作为上限，然后在数组中找到相同索引处的值 value .

例如:如果 sum 中的值是 270，我的程序应该找到位于 size 中索引 6 处的值 280并输出对应value[6]处的值.

#include <iostream>
#include <cmath>
#include <cstring>

using namespace std;

int main()
{
    double x = 0;
    double y = 0;
    double sum = 0;
    double size[27] = {24, 28, 32, 38, 48, 240, 280, 320, 360, 380,
                       420, 480, 560, 600, 640, 700, 720, 800, 840,
                       960, 980, 1120, 1200, 1280, 1440, 1680, 1920};

    double value[27] = {.0022, .0026, .0029, .0035, .0044, .0219,
                        .0256, .0292, .0328, .0384, .0438, .0513,
                        .0547, .0584, .0641,.0656, .073, .0766,
                        .0875, .0877, .0897, .1023, .1094, .1169,
                        .1313, .1531, .175};

    cout << "Enter width: " << endl;
    cin >> x;
    cout << "Enter height: " << endl;
    cin >> y;

    x = ceil(x) + 3;
    y = ceil(y) + 3;

    sum = x * y;
}

Answer 1

将您的代码更改为此 -

    double x = 0;
    double y = 0;
    double sum = 0;
    int size[27] = {24, 28, 32, 38, 48, 240, 280, 320, 360, 380,
    420, 480, 560, 600, 640, 700, 720, 800, 840, 960, 980, 1120, 1200, 1280, 1440, 1680, 1920};
    double value[27] = {.0022, .0026, .0029, .0035, .0044, .0219,
    .0256, .0292, .0328, .0384, .0438, .0513, .0547, .0584, .0641,.0656, .073, .0766, .0875, .0877, .0897, .1023, .1094, .1169, .1313, .1531, .175};

    cout << "Enter width: " << endl;
    cin >> x;
    cout << "Enter height: " << endl;
    cin >> y;

    x = ceil(x) + 3;
    y = ceil(y) + 3;

    sum = x * y;

    for (int i=0;i<27;i++)
    {
        if (size[i]>=sum)
        {
          cout<<value[i]<<endl; 
          break;
        }
        else if(i==26)
        {
            cout<<"No upper Bound find\n";
        }
    }

还有其他方法可以解决这个问题。但是正如您所说，您是初学者。我已经给出了简单的暴力破解解决方案。 :)