我正在尝试制作 C++ Template
可以存储模板值的类。但是,我需要在知道模板值的类型之前创建指向此类的指针。为此,我创建了一个摘要 Base
模板类继承自的类。我创建指向 Base
的指针,当分配它们时,我使用 basePtr = new Template<TYPE>
.
这里的问题是给Template
赋值。 .我能想到的每一种方法(我喜欢使用重载赋值运算符)都需要一个以模板数据类型作为形式参数的方法。因为Template
只能通过 Base
访问对象指针,我必须在 Base
中创建一个虚函数.但是,虚拟方法不能包含模板数据类型,Base
中的虚拟方法的签名必须与 Template
的签名匹配的方法。
这是我想要的示例:
class Base {
public:
/* THIS IS ILLEGAL - can't have template virtual method
template <class V>
virtual void operator =(const V& newValue) = 0;
*/
};
template <class ValueType>
class Template : public Base {
private:
ValueType *value;
public:
void operator =(const ValueType& newValue) {
*value = newValue;
}
};
int main() {
Base *theObject; // Datatype for template not known
theObject = new Template<string>; // At this point, it will be known
// NOW, THIS DOESN'T WORK - no virtual assignment overload in Base
*theObject = "Hello, world!";
return 0;
}
如果我以完全错误的方式解决这个问题,或者如果我的方法很愚蠢,我深表歉意——这是我第一次涉足真正的 OOD。有没有办法解决我没有看到的这个问题?我知道我可以在 Base
中创建一长串纯虚函数用不同的输入类型重载赋值运算符,像这样:
virtual void operator =(const string& newValue) = 0;
virtual void operator =(const int& newValue) = 0;
virtual void operator =(const long& newValue) = 0;
...
但是,我希望用户能够将自定义类对象(或者更可能是指向这些对象的指针)插入到 Template::value
中。 ,我无法用上述方法完成。
最佳答案
实现您想要实现的目标的一种方法是使用 Boost.Any (一个著名的只有头文件的库)。下面是一个演示。代码一步步注释,大家应该能看懂, here 是一个活生生的例子:
#include <stdexcept> // Standard header for exception classes
#include <string> // Standard header for std::string
#include <boost/any.hpp> // The Boost.Any library header
#include <iostream> // This program prints some output
class Base
{
public:
virtual void operator = (boost::any val) = 0;
// ^^^^^^^^^^
// This can hold (almost) "any" value
// You need a virtual destructor if you want to delete objects
// of subclasses of this class through a pointer to this class!
virtual ~Base() { }
};
template <class ValueType>
class Template : public Base
{
private:
ValueType value;
// ^^^^^^^^^
// I do not see why using a pointer in this case. Manual memory
// management just complicates things. However, if your really
// need to do it and your really know what you're doing, go ahead.
// Just remember to delete your pointer at destruction and not to
// dereference it before it points to an allocated object (in your
// original text, both of these things are NOT done correctly).
public:
virtual void operator = (boost::any val)
{
// Attempt a cast to detect if the value we are trying to
// assign to this object is of the appropriate type...
ValueType* pVal = boost::any_cast<ValueType>(&val);
if (pVal == nullptr)
{
// ...it is not! Throw an exception...
throw std::logic_error("Incompatible type");
}
// The value is OK: assign it...
value = *pVal;
}
};
int main()
{
Base *theObject;
theObject = new Template<std::string>;
try
{
// This assignment will succeed...
// Wrapping the string literal in a std::string object is necessary
// because boost::any cannot be initialized from an array (and in C++
// string literals are arrays of characters).
*theObject = std::string("Hello, world!");
// This assignment will fail!
*theObject = 1;
}
catch (std::logic_error const& e)
{
// Handle the exception...
std::cout << e.what();
}
delete theObject; // <=== DON'T FORGET THIS!
return 0;
}
关于c++ - 通过指向其非模板父类的指针将模板值分配给类模板,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15125730/