有摘要I1
并派生C1
.
有摘要I2
并派生C2
.
I1
有shared_ptr<I2>
.如何使用 boost serializaton 使它们可序列化?我正在尝试这样做,但我的应用程序出现异常。
#include <sstream>
#include <boost/shared_ptr.hpp>
#include <boost/archive/binary_oarchive.hpp>
#include <boost/archive/binary_iarchive.hpp>
#include <boost/serialization/shared_ptr.hpp>
struct I1
{
I1() {}
virtual ~I1() = 0 {}
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{
}
};
struct C1 : I1
{
virtual ~C1() {}
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{
ar & boost::serialization::base_object<I1>(*this);
}
};
struct I2
{
virtual ~I2() = 0 {}
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{
ar & p;
}
boost::shared_ptr<I1> p;
};
struct C2 : I2
{
C2() { p = boost::shared_ptr<I1>(new C1); }
virtual ~C2() { }
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{
ar & boost::serialization::base_object<I2>(*this);
}
};
int main()
{
C2 c2;
std::string s;
std::stringstream ss(s);
boost::archive::binary_oarchive oa(ss);
oa.register_type<I1>();
oa.register_type<C1>();
oa.register_type<I2>();
oa.register_type<C2>();
oa << c2;
boost::archive::binary_iarchive ia(ss);
//ia.register_type<I1>(); // cannot instantiate abstract class
ia.register_type<C1>();
//ia.register_type<I2>(); // cannot instantiate abstract class
ia.register_type<C2>();
ia >> c2;
}
最佳答案
boost 序列化文档说 here BOOST_CLASS_EXPORT
的有趣之处:
... BOOST_CLASS_EXPORT ...
Hence, the need for export is implied by the usage of a derived class that is manipulated via a pointer or reference to its base class.
您的 p
指针正是这样做的。将这些宏添加到您的代码中还可以摆脱来自 main 的丑陋的显式 register_type()
调用,这也很好 :)
所以,这段代码似乎可以在 VS2014 中编译和工作:
#include <sstream>
#include <boost/shared_ptr.hpp>
#include <boost/archive/binary_oarchive.hpp>
#include <boost/archive/binary_iarchive.hpp>
#include <boost/serialization/shared_ptr.hpp>
#include <boost/serialization/export.hpp>
struct I1
{
I1() {}
virtual ~I1() = 0 {}
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{
}
};
BOOST_CLASS_EXPORT(I1)
struct C1 : I1
{
virtual ~C1() {}
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{
ar & boost::serialization::base_object<I1>(*this);
}
};
BOOST_CLASS_EXPORT(C1)
struct I2
{
virtual ~I2() = 0 {}
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{
ar & p;
}
boost::shared_ptr<I1> p;
};
BOOST_CLASS_EXPORT(I2)
struct C2 : I2
{
C2() { p = boost::shared_ptr<I1>(new C1); }
virtual ~C2() { }
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{
ar & boost::serialization::base_object<I2>(*this);
}
};
BOOST_CLASS_EXPORT(C2)
int main()
{
C2 c2;
std::string s;
std::stringstream ss(s);
boost::archive::binary_oarchive oa(ss);
oa << c2;
boost::archive::binary_iarchive ia(ss);
ia >> c2;
}
不过,有趣的是,Boost 文档中的声明显然不适用于所有编译器,并且互联网上的许多代码示例在 VS2014 中都不起作用。
关于c++ - 如何使用boost使用shared_ptr成员序列化对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27110035/