c++ - 如何获得函数在 C++ 中执行的确切次数？

Question

#include<iostream>
using namespace std;

void callMe()
{
    int count=0;
    cout<<"I am called "<<++count<<" times!\n";
}

int main()
{
    callMe();
    callMe();
    callMe();
    callMe();
    return 0;
}

在这种情况下，输出将是

I am called 1 times!
I am called 1 times!
I am called 1 times!
I am called 1 times!

相反，我希望输出打印为

I am called 1 times!
I am called 2 times!
I am called 3 times!
I am called 4 times!

Answer 1

希望下面的代码片段能解决你的问题!

#include<iostream.h>

void callMe()
{
    static int count=0;
    cout << "I am called " << ++count << " times!\n";
}

int main()
{
    callMe();
    callMe();
    callMe();
    callMe();
    return 0;
}

这里的静态变量会保留它的值，并且会打印每次递增的计数!