嘿,如果用户输入的不是数字值,我试图让我的代码抛出错误。
这就是我到目前为止所做的,但是当我运行程序并输入一个字符而不是数字时,它只是跳过其余的输入和输出计算而实际上没有抛出任何错误消息。
#include "classes.h"
#include <iostream>
#include <math.h>
using namespace std;
//class constructor
thevenin::thevenin()
{
Resistance_1 = 1;
Resistance_2 = 1;
Resistance_3 = 1;
Voltage_1 = 1;
Voltage_2 = 1;
}
//empty class destructor
thevenin::~thevenin()
{
}
//output script for One loop problems
void thevenin::One_loop_thev(float tr1o, float tv1v)
{
//inputs
if (cin.fail()) //checking whether failbit or badbit is set
{
cout<<"error";
cin.clear(); //sets a new value for the stream's internal error state flags.
cin.ignore(numeric_limits<streamsize>::max(),'\n'); //ignores rest of the input ..
}
else;
cout<<"Please enter the value of R1"<<endl;
cin>>Resistance_1;
cout<<"Please enter the value of R2"<<endl;
cin>>Resistance_2;
cout<<"Please enter the value of R3"<<endl;
cin>>Resistance_3;
cout<<"Please enter the value of V1"<<endl;
cin>>Voltage_1;
//calculations
tv1v = (Voltage_1 * Resistance_3)/ (Resistance_1 + Resistance_3);
tr1o = Resistance_2 + ((Resistance_1*Resistance_3)/(Resistance_1+Resistance_3));
cout<<"The Thevenin equivalent resistance is: "<<tr1o<<"ohms"<<endl;
cout<<"The Thevenin equivalent voltage is: "<<tv1v<<"volts"<<endl;
我只是想知道我应该如何调整 if(cin.fail())
语句以使用我的代码。
最佳答案
当您尝试读入值时,流会遇到错误,因此您无法在 cin
之前检查错误。
抛出错误的一种方法是告诉 iostream
为您抛出错误:
cin.exceptions(istream::failbit);
但是,您应该处理出现的错误。一个小演示:
#include <iostream>
#include <limits>
using namespace std;
int main () {
cin.exceptions(istream::failbit);
float a;
while (!cin.eof()) {
try {
cin >> a;
cout << a<< '\n';
} catch (istream::failure& e) {
cout << "bad input\n";
cin.clear();
cin.ignore(numeric_limits<streamsize>::max(),'\n');
}
}
}
因此,对于您的代码(已编辑以添加重试):
//output script for One loop problems
void thevenin::One_loop_thev(float tr1o, float tv1v)
{
cin.exceptions(istream::failbit); // throw errors
while (true) {
try {
cout<<"Please enter the value of R1"<<endl;
cin>>Resistance_1;
cout<<"Please enter the value of R2"<<endl;
cin>>Resistance_2;
cout<<"Please enter the value of R3"<<endl;
cin>>Resistance_3;
cout<<"Please enter the value of V1"<<endl;
cin>>Voltage_1;
//calculations
tv1v = (Voltage_1 * Resistance_3)/ (Resistance_1 + Resistance_3);
tr1o = Resistance_2 + ((Resistance_1*Resistance_3)/(Resistance_1+Resistance_3));
cout<<"The Thevenin equivalent resistance is: "<<tr1o<<"ohms"<<endl;
cout<<"The Thevenin equivalent voltage is: "<<tv1v<<"volts"<<endl;
return; // break out of the loop
}
catch (istream::failure& e) {
cout<<"error";
cin.clear(); //sets a new value for the stream's internal error state flags.
cin.ignore(numeric_limits<streamsize>::max(),'\n'); //ignores rest of the input ..
}
}
}
关于c++ - float 的异常处理 C++,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32047385/