C++ 将 std::map 序列化为文件

Question

我有一个 C++ STL 映射，它是 int 和 customType 的映射。 customType 是一个结构体，它具有字符串和字符串列表，我如何将其序列化为文件。

示例结构:

struct customType{
string;
string;
int;
list<string>;
}

Answer 1

如果你不怕 BOOST，试试 BOOST 序列化: (模板代码，这里可能有一些错误...)

#include <boost/archive/binary_oarchive.hpp> 
#include <boost/archive/binary_iarchive.hpp> 
#include <boost/serialization/map.hpp> 
#include <boost/serialization/string.hpp> 
#include <boost/serialization/list.hpp> 

struct customType{
 string string1;
 string string2;
 int i;
 list<string> list;

// boost serialize 
private: 
    friend class boost::serialization::access; 
    template <typename Archive> void serialize(Archive &ar, const unsigned int version) { 
        ar & string1; 
        ar & string2; 
        ar & i;
        ar & list;
    } 
};

template <typename ClassTo> 
int Save(const string fname, const ClassTo &c) 
{ 
    ofstream f(fname.c_str(), ios::binary);
    if (f.fail()) return -1;
    boost::archive::binary_oarchive oa(f); 
    oa << c; 
    return 0;
} 

用法:

Save< map<int, customType> >("test.map", yourMap);